8/10 = 4/5 divide each by 2
Answer:
We want to find:
Here we can use Stirling's approximation, which says that for large values of n, we get:
Because here we are taking the limit when n tends to infinity, we can use this approximation.
Then we get.
Now we can just simplify this, so we get:
And we can rewrite it as:
The important part here is the exponent, as n tends to infinite, the exponent tends to zero.
Thus:
The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 150
R interest rate 0.025
T time?
3000=150 (1+0.025/12)^12t
Solve for t
3000/150=(1+0.025/12)^12t
Take the log
Log (3000/150)=log (1+0.025/12)×12t
12t=Log (3000/150)÷log (1+0.025/12)
T=(log(3,000÷150)÷log(1+0.025÷12))÷12
T=119.95 years
Answer
Given
Sean's house is currently worth $188,900.
According to a realtor, house prices in Sean's neighborhood will increase by 4.8% every year.
To prove
Formula
Where r is the rate in the decimal form.
As given
= 0.048
Put in the formula
Now also calculated monthly.
Formula
As given
= 0.048
Put in the formula
As the approximation quarterly growth rate of the value of sean's house is near the Compounded quarterly interest .
Thus Option (A) is correct.
i.e
The expression reveals the approximate quarterly growth rate of the value of Sean's house.
Answer:
4 bags
Step-by-step explanation:
⅔ ÷ ⅙
⅔ × 6 = 4