25 ounces of guacamole are still expected to be available from batch.
Step-by-step explanation:
Given,
Quantity of guacamole in one serving = 2.2 ounces
Quantity of guacamole in one batch = 80 ounces
Quantity of guacamole in 25 servings = 2.2*25 = 55 ounces
Guacamole left = Quantity in batch - Quantity of 25 servings
Guacamole left = 
25 ounces of guacamole are still expected to be available from batch.
Keywords: multiplication, subtraction
Learn more about subtraction at:
#LearnwithBrainly
(-6,-4)
the point D can shift left 2 units which would be at that point
Another way is to note that there are <span><span>(<span>104</span>)</span><span>(<span>104</span>)</span></span> (“10 choose 4”) ways to select 4 balls from a collection of 10. If 4 of those 10 balls are “special” in some way (in this case, “special” = “red”), then the number of ways to choose 4 special balls is <span><span>(<span>44</span>)</span><span>(<span>44</span>)</span></span>. (The factor of <span><span>(<span>60</span>)</span><span>(<span>60</span>)</span></span> is included to convey that, after choosing 4 special balls, we choose none of the 6 non-special balls.) This line of reasoning gives the second expression.
Answer: 0.0930
Step-by-step explanation:
As per given , we have
H0: μcoffee = 6
Ha: μcoffee < 6
She finds z = −1.68 with one-sided P-value P = 0.0465.
The P-value for two-tailed test is calculated by :
For z= -1.68 , we have
![=2(1-P(z\leq1.68))\ \ [\because\ P(Z>z)=1-P(Z\leq z)]](https://tex.z-dn.net/?f=%3D2%281-P%28z%5Cleq1.68%29%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D)
![=2(1-0.9535213)\ \ \ [\text{ NORM.S.DIST(z, TRUE}]\\\\=2( 0.0464787)=0.0929573\approx0.0930](https://tex.z-dn.net/?f=%3D2%281-0.9535213%29%5C%20%5C%20%5C%20%5B%5Ctext%7B%20NORM.S.DIST%28z%2C%20TRUE%7D%5D%5C%5C%5C%5C%3D2%28%200.0464787%29%3D0.0929573%5Capprox0.0930)
Hence, the correct two-sided P-value for z = −1.68 is 0.0930 .
Answer:
I guess this is the answer
