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Sav [38]
3 years ago
8

Tourists from a tour bus were asked about places they visited during their stay in a city. The results are shown in the table.

Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0
The answer is probaly 60 % i think
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AC=30

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Write twenty billion,one million thirty thousand and one as a number
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Can someone help i wil mark branliest to anyone who gets this right
Elan Coil [88]

Answer:

48.16

167.68

Step-by-step explanation:

New value =

36 - Percentage decrease =

36 - (14% × 36) =

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262 - Percentage decrease =

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7 0
3 years ago
Beth has seven $107 which shows the amount of money that has
dolphi86 [110]
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3 0
3 years ago
A research group is curious about their city’s participation in flu shot clinics. They suspect that there is a difference betwee
Kipish [7]

Answer:

t=\frac{(162-156)-0}{\sqrt{\frac{41^2}{22}+\frac{36^2}{20}}}}=0.505  

p_v =2*P(t_{40}>0.505)=0.61633  

Comparing the p value with the significance level \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the difference between the two groups is NOT significantly different.  

Step-by-step explanation:

Data given and notation

\bar X_{1}=162 represent the mean for sample of clinic attendees

\bar X_{2}=156 represent the mean for the sister city  

s_{1}=41 represent the sample standard deviation for 1  

s_{2}=36 represent the sample standard deviation for 2  

n_{1}=22 sample size for the group 2  

n_{2}=20 sample size for the group 2  

\alpha=0.05 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=22+20-2=40  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

t=\frac{(162-156)-0}{\sqrt{\frac{41^2}{22}+\frac{36^2}{20}}}}=0.505  

P value  

Since is a bilateral test the p value would be:  

p_v =2*P(t_{40}>0.505)=0.61633  

Comparing the p value with the significance level \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the difference between the two groups is NOT significantly different.  

3 0
3 years ago
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