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inn [45]
3 years ago
14

A soccer field is a rectangle 90 meters wide and 120 meters long. The coach asks players to run from one corner to the other cor

ner diagonally across the field.How far do the players run?
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
6 0
Take the width of the field (90 meters) and square it. Then take the length of the field (120 meters) and square it. The you add the two squares together and then find the square root of your answer. So basically 90^2 + 120^2 = 22500. then find the square root of 22500 which is 150 meters. 150 meters is your answer.
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The compound interest on Rs. 50000 at 4% per annum for 2 years compound annually is
statuscvo [17]

Answer:

$54080

Step-by-step explanation:

Step one:

given

principal= Rs. 50000

rate= 4%= 0.04

time= 2 years

Required

The final Amount A

Step two

Applying

A= P(1+r)^t

substitute

A= 50000(1+0.04)^t

A= 50000(1.04)^2

A= 50000*1.0816

A= 54080

$54080

6 0
3 years ago
Solve the equation for x<br> -2x = -32
grandymaker [24]

Answer:X=16

Step-by-step explanation:

first you divide -2 ,to -2x and also divide -32 by -2 and you get x=16

Hope this helped!!!

6 0
3 years ago
Suppose a triangle has sides 1 1 and one which of the following must be true
Jet001 [13]
If the triangle has 11 sides it not a triangle
5 0
3 years ago
Read 2 more answers
If the base of a Pyramid has an area of 144sq ft And if the slant higher of the pyramid is 10ft what would be the higher of the
pogonyaev

Answer:

the height of the pyramid is 8 ft

Step-by-step explanation:

Considering the base of the pyramid to be square whose area is 144 sq ft

This means the side of the base would be √144 = 12 ft.

Now, if you will imagine a pyramid we can easily observe that

Height(H) , slant height( L=10 ft) and half of the side length( 6ft) make a right angle triangle. We can easily calculate height from Pythagoras theorem as

10^2 = H^2 +6^2

⇒ H^2 = 10^2-6^2 = 100-36 = 64

⇒ H = 8 ft

Therefore, the height of the pyramid is 8 ft

3 0
3 years ago
I need help on my homework
soldi70 [24.7K]

Answer:

\displaystyle m\angle AED=32.5^\circ

Step-by-step explanation:

<u>Angles in a Circle</u>

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

Segments AE and DE are secants of the given circle. They form an exterior angle called AED.

The measure of an exterior angle is equal to half the difference of the measure of their intercepted arcs.

Intercepted arcs in the given circle are AD=113° and BC=48°. The exterior angle is:

\displaystyle m\angle AED=\frac{AD-BC}{2}

\displaystyle m\angle AED=\frac{113^\circ-48^\circ}{2}=\frac{65^\circ}{2}

\displaystyle m\angle AED=32.5^\circ

8 0
3 years ago
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