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Nuetrik [128]
3 years ago
7

Please help me asap!!!

Mathematics
1 answer:
saul85 [17]3 years ago
3 0

Answer:

It's B I think

Step-by-step explanation:

You might be interested in
3 coffees and 4 donuts cost $10.05. In the same cafeteria, 5 coffees and 7 donuts cost $17.15. How much do you have to pay for 4
MakcuM [25]

Answer

You need to pay $14.20 to get 4 coffees and 6 donuts.

Explanation

Let's say that the price of one coffee and x and the price of one donut is y.

In the first instance, 3x+4y=10.05.

In the second instance, 5x+7y=17.15.

You can use these equations to find the value of a coffee and the value of a donut.

We can find x and y using elimination. To do this, you should add or subtract one equation from another to "get rid" of a variable (I'll "get rid" of x). We can't just add or subtract the equations right now, since that wouldn't lead to 0x.

Multiply the first equation by 5, and the second equation by 3. After this, both equations will have 15x. Make sure to multiply each term by 5 and 3.

15x+20y=50.25. This means that 15 coffees and 20 donuts is $50.25.

15x+21y=51.45. This means that 15 coffees and 21 donuts is 51.45.

Now since there are an equal number of coffees, we can subtract these equations.

(15x+21y=51.45)-(15x+20y=50.25) equals y=1.20 (a donut costs $1.20).

Plug the price of the donut into y to find x; 3x+4(1.20)=10.05. The value of x is 1.75. The price of a coffee is 1.75.

You can multiply 1.75 by 4 to find the price of 4 coffees and 1.20 by 6 to find the price of 6 donuts.

1.75*4 is 7.00 and 1.20*6 is 7.20.

You can add those to find the total price; 7.00+7.20=14.20.

5 0
3 years ago
74% of freshmen entering public high schools in 2006 graduated with their class in 2010. A random sample of 81 freshmen is selec
Assoli18 [71]

Answer: Probability that the proportion of students who graduated is greater than 0.743 is P = 0.4755

Step-by-step explanation:

Given that,

Probability of freshmen entering public high schools in 2006 graduated with their class in 2010, p = 0.74

Random sample of freshman, n = 81

Utilizing central limit theorem,

P(\hat{p}

So,

(P(\hat{p}>0.743) = P(Z>0.743 - \frac{0.74}{\sqrt{\frac{0.74(1-0.74)}{81} }  } )

= P( Z > 0.0616)

= 0.4755 ⇒ probability that the proportion of students who graduated is greater than 0.743.

7 0
3 years ago
Maria, Carolina and Pedro receives $1600 from their grandfather in ratio 7:5:4. calculate share of each.
Nimfa-mama [501]

Step-by-step explanation:

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>total</em><em> </em><em>money </em><em>received</em><em> </em><em>by </em><em>them </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>the </em><em>given </em><em>ratio </em><em>are </em><em> </em><em>7</em><em>:</em><em>5</em><em>:</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>let </em><em>the </em><em>ratio </em><em>be </em><em>X </em><em>,</em><em>now</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>Maria </em><em>=</em><em> </em><em>7</em><em>X</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>Carolina</em><em> </em><em>=</em><em> </em><em>5</em><em>X</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>Pedro </em><em>=</em><em> </em><em>4</em><em>X</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>w</em><em>e </em><em>know </em><em>whole </em><em>money </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>so,</em><em> </em><em>adding</em><em> </em><em>all </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em>. </em><em>7</em><em>x</em><em> </em><em>+</em><em> </em><em>5</em><em>x</em><em> </em><em>+</em><em> </em><em>4</em><em>x</em><em> </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>1</em><em>6</em><em>x</em><em> </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em> </em><em>x=</em><em> </em><em>$</em><em>1</em><em>6</em><em>0</em><em>0</em><em>/</em><em>1</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em>. </em><em>x </em><em>=</em><em> </em><em>$</em><em>1</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>now </em><em>Maria</em><em> </em><em>=</em><em> </em><em>7</em><em>*</em><em>1</em><em>0</em><em>0</em><em> </em><em>=</em><em> </em><em>$</em><em>7</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Carolina</em><em> </em><em>=</em><em> </em><em>5</em><em>*</em><em>1</em><em>0</em><em>0</em><em> </em><em>=</em><em> </em><em>$</em><em>5</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>Pedro</em><em> </em><em>=</em><em> </em><em>4</em><em>*</em><em>1</em><em>0</em><em>0</em><em> </em><em>=</em><em> </em><em>$</em><em>4</em><em>0</em><em>0</em>

<em> </em><em> </em><em> </em><em>hope it</em><em> helps</em>

8 0
3 years ago
Changle. Show all work. Round each length to the nearest tenth and each angle to the
Sedaia [141]

Answer:

Part 1) BC=12.2\ units

Part 2) m\angle A=55^o

Part 3) m\angle C=35^o

Step-by-step explanation:

Part 1) Find AC

we know that

In the right triangle ABC of the figure

Applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=7^2+10^2

AC^2=149\\AC=12.2\ units

Part 2) Find the measure of angle A

we know that

In the right triangle ABC

tan(A)=\frac{BC}{AB} ----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{10}{7}

using a calculator

m\angle A=tan^{-1}(\frac{10}{7})=55^o

Part 3) Find the measure of angle C

we know that

In the right triangle ABC

m\angle A+m\angle C=90^o ----> by complementary angles

substitute the given value

55^o+m\angle C=90^o

m\angle C=90^o-55^o=35^o

8 0
3 years ago
Are same side exterior angles always congruent
Feliz [49]

Answer: Same-side interior angles are NOT always congruent.

8 0
3 years ago
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