If the width is 15, and the scale factor from width to length is 3:2, then you will have to divide 15 by 3 to get your original width.
15/3 = 5.
5 is your original width.
Answer:
Step-by-step explanation:
<u>Given Data:</u>
Circumference = C = 443 ft
<u>Required:</u>
Diameter = d = ?
<u>Formula:</u>
d = C / π
<u>Solution:</u>
d = 443 / 3.14
d = 141.0 feet
d = 141 feet
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
value if a =
Step-by-step explanation:
here's the solution :-
=》
![\frac{ 2(\sqrt{m}) {}^{3} }{ \sqrt[4]{m} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%202%28%5Csqrt%7Bm%7D%29%20%20%7B%7D%5E%7B3%7D%20%7D%7B%20%5Csqrt%5B4%5D%7Bm%7D%20%7D%20)
=》
=》
=》
=》
=》
so, a = 5/4
You have the length of the sides? If not: a and b is the length of the scratch, h is the height <span>This lateral surface area = 2ah+2bh=2h(a+b)</span>
Answer:
ok so basically...idk how to explain it but i'll give u an example l-8l = 8 or l8l or l-6l = l6l, i don't know if u understand me, but basically it's like the.....opposite of that number or the absolute value
