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sesenic [268]
1 year ago
14

Solve: 2(1 - 5k) = 2k + 38

Mathematics
1 answer:
Nonamiya [84]1 year ago
5 0

k=-3

1) Let's solve for k, the following expression:

2(1 - 5k) = 2k + 38​ <em>Distribute the factor 2</em>

2 -10k = 2k +38 <em>Subtract 2 from both sides and 2k</em>

-10k -2k = 38 -2

-12k = 36 <em>Divide by -1</em>

12k=-36 <em>Divide both sides by 12</em>

k= -3

2) So k is equal to -3 in this equation.

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The first three steps of completing the square to solve the quadratic equation x^2 +4x-6=0, are shown below
GarryVolchara [31]

Answer: x=sqrt10-2, x=-sqrt10-2

Step-by-step explanation: square root both sides of the equation.

x+2=sqrt10,-sqrt10

subtract 2 from both sides of the equation

x=sqrt10-2, -sqrt10-2

5 0
4 years ago
Peach paint is 1 part yellow to 3 parts
katrin2010 [14]

Answer:

8/3

Step-by-step explanation:

3 parts yellow to 2 parts red

4 parts yellow to x parts red

x=4*2/3 =8/3 parts red.

If it is right then there you go

8 0
2 years ago
Denise is constructing a square. she has already used her straightedge and compass to construct the circle, lines, and arcs show
Novosadov [1.4K]
What should denise do for her next step?

Answer: Out of all the options presented above the one that best represents the next step that denise should take after already using her straightedge and compass to construct the circle, lines, and arcs is to use the straightedge to draw line ac, line ad, line bc, and line bd. use the compass and straightedge to construct the bisector of ∠cpb∠cpb. Please see the attachment as reference to how it should look like once it is completed.

I hope it helps, Regards.
3 0
4 years ago
Can anyone help me with this?
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<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em> </em><em>.</em><em>.</em>

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3 years ago
10. Simplify the rational expression by rationalizing the denominator. 3 sqrt 160/sqrt 1350x A) 2 sqrt 15x/15x B) 3 sqrt 160/135
Viefleur [7K]
The simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.

First we must simplify the expression:
\frac{3 \sqrt{160} }{\sqrt{1350x} } =  \frac{12 \sqrt{10} }{15 \sqrt{6x} } =  \frac{4 \sqrt{10} }{5 \sqrt{6x} }

Then we factor the rational parts and cancel it out:
\frac{4 \sqrt{2} \sqrt{5} }{5 \sqrt{2} \sqrt{3x} } = \frac{4\sqrt{5} }{5\sqrt{3x} }

Then we rationalize the expression:
\frac{4\sqrt{5} }{5\sqrt{3x} } * \frac{\sqrt{3x} }{\sqrt{3x} } = \frac{4 \sqrt{15x} }{5*3x} = \frac{4 \sqrt{15x} }{15x}

<span>Finally, the simplified expression by rationalizing the denominator is (C)\frac{4 \sqrt{15x} }{15x}.</span>
7 0
3 years ago
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