2 years ago

Simplify [2 (cos 210 + i sin 210)]^2

1 answer:

4 0

2{(cos^210+isin^210)}^2

2(cos^210-sin^10+2i*cos10*sin10)

2(cos20+i*sin20)

cos^2Ф-sin^2Ф=cos2Ф and 2sinФcosФ=sin2Ф here Ф=10°

You might be interested in

lisov135 [29]

3x²-8x+4=0
(3x-2) (x-2)=0
x=2/3 , x = 2
Hence, the polynomial has two positive roots.
Option A is the correct choice.

8 0

2 years ago

strojnjashka [21]

Step-by-step explanation:

Since AD bisects BC,

BD = DC.

Therefore 5x - 10 = 3x + 10 and x = 10.

4 0

3 years ago

son4ous [18]

Subtract 43 from both sides
-6p=-30

Divide both sides by -6
p=5

Final answer: p=5

7 0

3 years ago

ryzh [129]

Answer:

i have solved them . if u can't understand. .. ask me XD

5 0

2 years ago

muminat

Answer:

I’m backk

Step-by-step explanation:

5 0

2 years ago