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soldi70 [24.7K]
3 years ago
10

Simplify [2 (cos 210 + i sin 210)]^2

Mathematics
1 answer:
Andru [333]3 years ago
4 0
2{(cos^210+isin^210)}^2

2(cos^210-sin^10+2i*cos10*sin10)

2(cos20+i*sin20)

cos^2Ф-sin^2Ф=cos2Ф and 2sinФcosФ=sin2Ф here Ф=10°

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Calculate the missing value. (Not drawn to scale.)
True [87]

Answer:5in

Step-by-step explanation:

1. Identify the triangle

you are given a right triangle with the hypotonus missing and are given the side lengths 3 and 4 you know the hypotonus is 5 by the 3,4,5 Pythagorean tripe, if you do not notice this it can be solved with the Pythagorean theorem a^2+b^2=c^2

2. solve (if not done with 3,4,5 triple)

3^2+4^2=c^2

9+16=c^2

25=c^2

5=c | square root both sides to cancel the square

5 0
1 year ago
The answer to the picture please
Vinil7 [7]

the required ans is 3√b+b/3b

8 0
3 years ago
Find the common ratio of the sequence -164, -82, -41, -20.5
Aleks [24]

Answer:

r = \frac{1}{2}

Step-by-step explanation:

The common ratio r of a geometric sequence is

r = \frac{a_{2} }{a_{1} } = \frac{a_{3} }{a_{2} } = \frac{a_{4} }{a_{3} } = ......

r = \frac{-82}{-164} = \frac{-41}{-82} = \frac{1}{2}

5 0
3 years ago
What is the value of 3 3/8+1/2 ÷ 4/5 × 2​
Strike441 [17]

Answer:

ans: 37/ 32

Step-by-step explanation:

(33/8 + 1/2 ) / ( 4/5 ×2)

= { ( 33 + 4) / 8} / ( 8 / 2)

= 37/ (4×8)

= 37 / 32

6 0
3 years ago
A booster club sells raffle tickets • Before tickets go on sale to the public, 120 tickets are sold to student athletes. • After
GaryK [48]

Answer:

The top graph.

Step by step:

Before the tickets go on sale, 120 tickets were already sold.

After that, the tickets sell at a constant rate for a total of 8 hours.

At the end of this time, all the tickets were sold (we have 0 tickets left)

If x (horizontal axis) represents the hours since tickets go on sale, and y (vertical axis) represents the number of raffle tickets sold.

Then, at x = 0, we should already see y = 120

Because we start with 120 tickets sold.

Then, as x increases, the number of tickets sold also should increase, until we get x = 8 hours, where y stops increasing because all tickets are already sold.

Then we should have an increasing line that stops increasing at x = 8 hours.

Then the correct option is the above graph, where we have:

An increasing line.

y = 120 in the vertical axis (y = 120 when x = 0)

3 0
3 years ago
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