When the cells undergo late apoptosis, the membrane structure is destroyed and the nuclear structure can be selectively visualized by Hoechst 33342/PI.
https://www.creative-bioarray.com/support/double-staining-apoptosis-assay-hoechst33342-pi.htm
Answer:
A. Supine is lying on the back; prone is lying with the back facing up
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Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Protein Function may be terminated, disrupted, destruction of both the secondary and tertiary structure through the process called DENATURATION. Denaturation process does not break the primary structures since the link or sequence of peptide bond are greatly hold by Hydrogen bonding.
The best and most correct answer among the choices provided by your question is the second choice or letter B.
Reptiles don't sit on their eggs like birds do because r<span>eptile eggs are not amniotic and have no shell, so sitting on them would crush them.</span>
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