Question

Please answer quickly, more might be coming soon. 50 Points!

Answer 1

Answer:

2) ∠SDH and ∠SDT are right angles because SD ⊥ HT.

3) $\bar{SH}\cong \bar{ST}$ as it is given in the question.

4) $\bar{SD}\cong \bar{SD}$  is the reflexive property.

5) ΔSHD ≅ ΔSTD by RHS congruency.

Step-by-step explanation:

Given in the question:

$\bar{SH}\cong \bar{ST}\\\bar{SD}\perp \bar{HT}$

In ΔSHD and ΔSTD

$\bar{SH}\cong \bar{ST}$   (Given)

$\angle SDH\cong \angle SDT=90^o$    (SD ⊥ HT)

$\bar{SD}\cong \bar{SD}$ (Common)

Therefore, $\Delta SHD\cong \Delta STD$   (By RHS rule)

Reflexive property of congruency is defined as the property in which something is equal to itself. Hence, the reflexive property of these two triangles is $\bar{SD}\cong \bar{SD}$