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fredd [130]
3 years ago
12

Two equations are shown:

Mathematics
2 answers:
AysviL [449]3 years ago
8 0

Answer:

Both are linear.

Step-by-step explanation:

I graphed both of the equations on the graph below to show you that both of them are linear.

kondaur [170]3 years ago
6 0

Answer:

Both are linear

Step-by-step explanation:

As long as the equation can be written in y = mx + b form, then it is linear.

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If the graph of f(x) has the point (2,7) then what is one point that will be on the graph of f-1(x)
IRINA_888 [86]

The graph of f^-1 (x) is called the inverse function of f (x). The relationship between the two is that the point (x,y) is on the graph of f (x) if and only if the point (y,x) is on the graph of f^-1 (x).

This means that if the point (2, 7) is on f (x), therefore the point (7, 2) is on f^-1 (x).

<span>Answer: (7, 2)</span>

6 0
3 years ago
Read 2 more answers
-2/9x+(-7/9y)+(-7/10x+(-2/3)
coldgirl [10]

Step-by-step explanation:

=-32-9 08 3X-97y

9- 2⋅ x+9- 7⋅ y+(1 0- 7⋅ x+3- 2)

5 0
3 years ago
Answer answer answer answer
Mice21 [21]

Answer:

12 \leqslant x < 26

4 0
3 years ago
3 5/5
MAXImum [283]

Answer:

4

Step-by-step explanation:

7 0
3 years ago
A model car travels around a circular track with radius 5 feet. Let Z denote the distance between the model car and a fixed poin
Eddi Din [679]

Answer:

\frac{dZ}{dt}= \frac{40}{\sqrt{545} } , so the model car is moving away from the fixed point at a rate of approximately 1.7 feet per second.

Step-by-step explanation:

The functions x and y satisfy (x−20)^2+y^2=25 and differentiating gives 2(x−20)dx/dt+2y dy/dt=0. Substituting the three known values and solving for dy/dt yields dy/dt=−32. Since Z=x^2+y^2−−−−−−√, dZ/dt=(2x ^ dx/dt+2y^dy/dt) / 2x2+y2√. Substituting Since Substituting for x, y,\frac{dx}{dt} , and \frac{dy}{dt} gives \frac{dZ}{dt}= \frac{40}{\sqrt{545} } ,

5 0
3 years ago
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