Find a recursive formula for the sequence: 3, -5, 11, -21
1 answer:
The correct option is the last:
In fact, every term in the sequence is one more than twice the opposite of the previous one:
We start with 3. Twice its opposite is -6. Plus one, we get -5.
We start with -5. Twice its opposite is 10. Plus one, we get 11.
We start with 11. Twice its opposite is -22. Plus one, we get -21.
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The asymptotes are where the graph is undefined. Since: tan(x) =sin(x)/cos(x)
It is where cos(4x-π) = 0
cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2
4x - π = π/2
4x = π/2 + π
4x = 3π/2
x = 3π/8
4x - π = 3π/2
4x = 3π/2 + π
4x = 5π/2
x = 5π/8
This ones outside the interval (5π/8 > π/2) , try -π/2
4x - π = -π/2
4x = -π/2 + π
4x = π/2
x = π/8
Asymptotes are π/8 and 3π/8