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4 years ago

15

a person standing at a ridge in the grand canyon throws a penny upeard and toward the pit of the canyon. The height of the penny

is given by the function h(t)=-12t^(2)+80t. What is the maximum height that the penny will reach?

1 answer:

Lelechka [254]4 years ago

4 0

I believe its 80 if you derive it out, but there is no units of measurement.

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A number increases by 10%, and then decreases by 10%. Will the result be greater than, less than, or equal to the original numbe

elena-s [515]

Given that the number is x,
10% increase will give us a new number of:
110/100*x
=1.1x
10% decrease will give us a new number of:
90/100*1.1x
=0.99x
This implies the new number is less than the original number

3 0

3 years ago

A box is filled with thirty six plates. How many boxes can be filled with a thousand plates?

Yuki888 [10]

Hello there ^ _ ^

We know that 36 plates filled 1 box
if we have 1000 plates, how many box it would fill.

All we have to do is divide 1000 by 36 to find the answer.

1000/ 36 = 27.77777 or you can just say 28

I hope this help!

4 0

3 years ago

Read 2 more answers

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$

8 0

3 years ago

Given f(x) = 3/4 x + 12, find the value of x when f(x) = x.

12345 [234]

Answer:

The rigth answer is, x = 1

Step-by-step explanation:

As:

f (x) = 3/4 x + 12

They separate the terms:

3/4 x = 12

Then, what you are multiplying happens to divide:

x = 12/1/3/4

Media are divided by means and ends with ends, and we have as a result that:

x = 3/3 = 1

5 0

3 years ago

Please help with 11,12,13

faltersainse [42]

Problem 11

<h3>Answer: h = 2A/b</h3>

------------------

Explanation:

We need to get h by itself. To do so, we first multiply both sides by 2. Then we divide both sides by b

A = (1/2)*b*h

2A = b*h

b*h = 2A

h = 2A/b

================================================

Problem 12

<h3>Answers:</h3>

Equation: (n+2)/5 = 14
Solution to that equation: n = 68

------------------

Explanation:

The number n is increased by 2 to get n+2

Then we divide by 5 to get (n+2)/5

This is set equal to 14 to get the equation (n+2)/5 = 14

Solving the equation would look like this

(n+2)/5 = 14

n+2 = 5*14 .... multiply both sides by 5

n+2 = 70

n = 70-2 .... subtract 2 from both sides

n = 68

================================================

Problem 13

<h3>Answer: Not a solution</h3>

------------------

Explanation:

We'll replace every copy of x with -3 and simplify

-2x + 5 > 13

-2*(-3) + 5 > 13

6 + 5 > 13

11 > 13

The last inequality is false because 11 is not greater than 13. Since the last inequality is false, this makes the first inequality false when x = -3.

Therefore, x = -3 is not a solution.

3 0

3 years ago