Answer:
h(t) = = -16t^2 + 167t + 135
Step-by-step explanation:
This is an equation of motion of an object umder a constant acceleration(here it is the acceleration due to gravity);
h(t) = = -16t^2 + 167t + 135.
Note: t is the time in seconds and h is the height in feet at time t.
from question d = 16t^2 = 56-4t
=》 16t^2 -56 + 4t =0
=》 4t^2 - 14 + t = 0
=》 (4t-7)(t+2) =0
=》 t = 1.75 seconds
<span>The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.
have four terms and 1 constant
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