Let this number be represented by the variable "n"
product of 4 and n is multiplying4 and n
4 * n = 5.6
divide 4 to both sides to isolate the variable on one side
n=1.4
Answer:
Step-by-step explanation:
Michael works for 25 hours
Answer:
The probability of selecting both yellow is 5/22.
Step-by-step explanation:
Given the number of yellow marbles = 6
Black marbles = 4
Purple marble = 2
Now find the total number of marbles in the jar.
Thus total marbles = Yellow marbles + Black marbles + Purples marble
Now insert the values in the above formula.
Total marbles = 6 + 4 + 2
Total marbles = 12
The probability of 2 yellow marble:
Thus, the probability of selecting both yellow is 5/22.
The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.
The measurement of two of the walls is 2.86 metres and 3.16 metre
Area of the two walls = 2(length x breadth)
Area = 2(2.86 x 3.16) = 18.0752 m²
The measurement of the other two walls is 2.86 metres and 3.42 metres
Area of the two walls = 2(length × breadth)
Area = 2(2.86 × 3.42) = 19.5624 m²
Total area = 18.0752 + 19.5624 = 37.6376 m²
If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be
No. of cans = Total area/Area covered by one can of paint
No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)
The function "choose k from n", nCk, is defined as
nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial
a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.
b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
(2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
