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irga5000 [103]
2 years ago
9

When f(x) = x2+9 and g(x) = x-9, find f(x)-g(x).

Mathematics
1 answer:
ohaa [14]2 years ago
5 0

Answer:

\huge{ \boxed{ \sf{ {x}^{2}  - x + 18}}}

Step-by-step explanation:

\underline{ \text{Given}}:

\sf{f(x) =  {x}^{2} +9  \: and \:  g(x) = x-9}

\underline{ \text{To \: find}} :  \sf{ \: f(x) \:  -  \: g(x)}

Put the values:

\mapsto{ \sf{ {x}^{2}  + 9 - ( x  - 9)}}

While subtracting , sign of each term of the second expression changes.

\mapsto{ \sf{ {x}^{2}  + 9 - x + 9}}

Add the numbers : 9 and 9

\mapsto{ \boxed{ \sf{{x}^{2}  - x + 18}}}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

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2 years ago
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now, by traditional method, as "x" progresses towards the positive infinitity, it becomes 100, 10000, 10000000, 1000000000 and so on, and notice, the limit of the numerator becomes large.

BUT, notice the denominator, for the same values of "x", the denominator becomes larg"er" than the numerator on every iteration, ever becoming larger and larger, and yielding a fraction whose denominator is larger than the numerator.

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3 years ago
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bezimeni [28]

-3+8=5

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4 0
3 years ago
Yolanda owns 4 rabbits. She expects the number of rabbits to double every year.
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--------------------------------------------

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3 years ago
Read 2 more answers
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