This region as the same area as the one in your previous question.
Pr[1 < <em>Z</em> < 2] = Pr[-2 < <em>Z</em> < -1] ≈ 0.14
= 0.41667
= 0.375
You are correct! 0.41667>0.375
Answer:
Jshhj d
Step-by-step explanation:
Hhhh xgkavhs s fnjx
Answer:
B. x = 15, m∠Q = 75°
Step-by-step explanation:
Given:
m∠P = 105°
m∠Q = 
Angles P and Q are supplementary angles
To find value of
and m∠Q.
Solution:
[Sum of supplementary angles =180°]
[Substitution ∵ m∠P = 105° and m∠Q =
]
Subtracting both sides by 105°.

Dividing both sides by 5.
∴ 
∴ 
Answer:
2
Step-by-step explanation:
So to figure this out we just need to flip the values of x and y in the table and then redefine that as the function g(x), because an inverse is essentially the reverse!
So if we flipped x and y's for f(x). We would see that our output or y of g(x) is -3 when x = 2, or in other words g(2) = -3. This means that we are now going to solve for when f(-3). So now lets look at the table and find the value at x = -3 for f(x). This value is 2, so the value of f(g(2)) = 2.
*In the future*
When you have a composite function of two inverses they essentially cancel out and would leave whatever the value of x is. So if we know f(x) and g(x) were inverses the value of f(g(2)) would just be 2.
For example:
ln(x) and e^x are inverses so if I had a composition like this:
The answer to this would be 2 because these inverse functions "'cancel" out
So
