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Likurg_2 [28]
3 years ago
10

Draw the correct logic gates for each of these truth tables

Computers and Technology
1 answer:
timurjin [86]3 years ago
6 0

The logic gates are shown right below your truth tables... lol.


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Which relation is created with the primary key associated with the relationship or associative entity, plus any non-key attribut
konstantin123 [22]

Answer:

- Transform binary or unary M:N relationship or associative entity with its own key.

Explanation:

Transform binary relation is described as the method through which a decimal can easily be converted into binary while the unary relationship is described as a relationship in which both the two participants occurs from the same entity.

In the given case, 'transform binary or unary M:N relationship' can be created using 'the primary key linked with the relationship plus any non-key aspects of the relationship and the primary keys of the related entities' as it displays the existence of a relationship between the occurrences of a similar set of the entity i.e. associative entity here.

5 0
3 years ago
Suppose that the tuition for a university is $10,000 this year and increases 4% every year. In one year, the tuition will be $10
seropon [69]

Answer:

<em>The programming language is not stated; however, I'll answer using Python programming language (</em><em>Se</em><em>e attachment</em><em> </em><em>for</em><em> </em><em>proper </em><em>for</em><em>mat</em><em>)</em>

tuition = 10000

rate = 0.04

for i in range(1,15):

tuition = tuition + tuition * rate

if i <= 10:

print("Year "+str(i)+" tuition:",end=" ")

print(round(tuition,2))

if i == 14:

print("Tuition 4th year after:",end=" ")

print(round(tuition,2))

Explanation:

<em>The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively</em>

tuition = 10000

rate = 0.04

<em>The next line iterates from year 1 to year 14</em>

for i in range(1,15):

<em>This line calculates the tuition for each year</em>

tuition = tuition + tuition * rate

<em>The next 3 lines prints the tuition for year 1 to year 10</em>

if i <= 10:

print("Year "+str(i)+" tuition:",end=" ")

print(round(tuition,2))

<em>The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)</em>

if i == 14:

print("Tuition 4th year after:",end=" ")

print(round(tuition,2))

7 0
3 years ago
To view paragraph marks, click on the ______ tab, in the paragraph group, click show/hide
sergejj [24]

Answer:

Home

Explanation:

Thank Quizlet, lol!

3 0
3 years ago
Java and Python are considered rapid development programming languages?<br><br> True<br><br> False
Zepler [3.9K]
That is true because Java was considered a rapid development programming language
8 0
4 years ago
Read 2 more answers
Write a basic program that performs simple file and mathematical operations.
Ostrovityanka [42]

Answer:

Explanation:

I have written the Python program based on your requirements.

Just give the path of the input file and the path for the output file correctly where you want to place the output file.

In, my code - I have given my computer's path to the input and output file.

You just change the path correctly

My code works perfectly and I have tested the code with your inputs.

It gives the exact output that you need.

I have attached the Output that I got by running the below program.

Code:

month_list={ "january":"1","february":"2", "march":"3","april":"4", "may":"5", "june":"6","july":"7", "august":"8", "september":"9","october":"10", "november":"11", "december":"12"} input_file=open('C:\\Users\\Desktop\\inputDates.txt', 'r') output_file=open('C:\\Users\\Desktop\\parsedDates.txt','w') for each in input_file: if each!="-1": lis=each.split() if len (lis) >=3: month=lis [0] day=lis[1] year=lis [2] if month.lower() in month_list: comma=day[-1] if comma==',': day=day[:len (day)-1] month_number=month_list[month.lower()] ans-month_number+"/"+day+"/"+year output_file.write (ans) output_file.write("\n") output_file.close() input_file.close()

- O X parsedDates - Notepad File Edit Format View Help 3/1/1990 12/13/2003

- X inputDates - Notepad File Edit Format View Help March 1, 1990 April 2 1995 7/15/20 December 13, 2003 -1

cheers i hope this helped !!

7 0
4 years ago
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