I’m not 100% sure but I think it’s a padlock that represents it
Answer:
"Cross-training
" seems to be the right response.
Explanation:
- Cross-training seems to be the method of constructing a multi-professional workers staff with incentive plans to make sure that they must have the same tools to complete different occupational tasks throughout the organization.
- This will be a very broad approach besides randomized controlled training methods, both maximum and minimum frequency, for generations.
The answer is C) Availability.
Although the company is addressing scalability by adding more servers, the question is asking for security requirement. Therefore we need to choose one of the principles from CIA triad which includes confidentiality, integrity, and availability.
Integrity involves keeping the data accurate and confidentiality involves keeping the data between the sender and intended recipient(s). That being said, scalability and availability are the possible answers.
C) Availability is the best answer because it is part of the CIA triad.
Note: Another resource to look at for cyber security principles would be the Parkerian Hexad.
The two best practices for creating ads are:
- Include three to five ads and at least three extensions in each ad group.
- Optimize the campaign’s ad rotation for clicks or conversion actions.
<h3>How do one Create one responsive search ad per ad group?</h3>
In any ad group, one need to have at least a single responsive search ad.
Note that this will help to optimize one's performance, and as such, the two best practices for creating ads are:
- Include three to five ads and at least three extensions in each ad group.
- Optimize the campaign’s ad rotation for clicks or conversion actions.
Learn more about ads from
brainly.com/question/1658517
#SPJ1
Answer:
C++ code is given below
Explanation:
#include <iostream>
#include <cctype>
#include <string.h>
#include <cstring>
#include <sstream>
using namespace std;
struct Car {
public:
char reportingMark[5];
int carNumber;
string kind;
bool loaded;
string destination;
};
void input(Car *);
void output(Car *);
int main() {
Car *T = new Car;
input(T);
output(T);
delete T;
return 0;
}
void input(Car *T)
{
string str, s;
cout << " Enter the reporting mark as a 5 or less character uppercase string: ";
cin >> str;
for (int i = 0; i < str.length(); i++)
T->reportingMark[i] = toupper(str[i]);
cout << " Enter the car number: ";
cin >> T->carNumber;
cout << " Enter the kind: ";
cin >> T->kind;
cout << " Enter the loaded status as true or false: ";
cin >> s;
istringstream(s) >> boolalpha >> T->loaded;
if (T->loaded == true) {
cout << " Enter the destination: ";
cin.ignore();
getline(cin, T->destination);
}
else
T->destination = "NONE";
}
void output(Car *T)
{
cout << " Reporting Mark: " << T->reportingMark;
cout << " Car Number: " << T->carNumber;
cout << " Kind: " << T->kind;
cout << " Loaded Status: " << boolalpha << T->loaded;
cout << " Destination: " << T->destination << " ";
}
