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3 years ago

Terry made a plastic birdhouse with the dimensions shown below. How many square inches

Mathematics

2 answers:

xxMikexx [17]3 years ago

7 0

Answer:

376 squared inches for the hole bird house, 60 for the side with the whole.

Step-by-step explanation:

1 side is 60 inches squared, another is 48 inches squared, and another is 80 inches squared, and there are two of each side so you get 120+96+160= 376.

gayaneshka [121]3 years ago

5 0

376

Solving Steps:

(6x10)(2)+(8x6)(2)+(8x10)(2)

=376

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Tickets to Dundee crowns mr.dchs are $3 for students and $5 for adults. The number of adult tickets sold was 195 more than the n

Maurinko [17]

Answer: number of tickets sold to adult = 566

Step-by-step explanation:

Let x = number of tickets sold by DCHS to students.

Let y = number of tickets sold DCHS to adults.

Tickets to Dundee crowns mr.dchs are $3 for students and $5 for adults.

This means cost of total tickets sold to students and adults is $3x and $5y respectively.

If DCHS collected $3943 for the tickets, then we have

3x + 5y = 3943 - - - - - -1

The number of adult tickets sold was 195 more than the number of student tickets. This means

y = x +195.

Put y = x +195 in equation 1

3x + 5(x+195) = 3943

3x + 5x + 975= 3943

8x +975=3943

8x = 3943-975= 2968

x = 2968/8 = 371

y = 371 + 195= 566

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3 years ago

How do I check my work for 66÷6996

Digiron [165]

You multiply the dividend and the quotient

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3 years ago

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What is the value of x in the equation 2x + 3y = 36, when y = 6?

atroni [7]

X would equal 9. Subtract 18 from both sides then divide by two to get 9 as X

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3 years ago

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Find the surface area of the sphere with the given dimension. Leave your answer in terms of pi

AfilCa [17]

A you just divide bro

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3 years ago

Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i

aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

$P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175$

Positive when there is raritanium:

98% of 13%

$P(A) = 0.98*0.13 = 0.1274$

What is the probability the rock sample actually contains raritanium?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967$

0.967 = 96.7% probability the rock sample actually contains raritanium

7 0

3 years ago