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3 years ago

9

Plz Need help ASAP !!!!!!!!!!!

2 answers:

Sidana [21]3 years ago

5 0

its c ................

Nesterboy [21]3 years ago

4 0

This is hard you’re gonna have to let me figure it out first

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Larry’s pet store made $30 before a pipe burst and he had to close early to get it fixed. He realized that he lost Three-fourths

LekaFEV [45]

Answer: replace 8 for x now you have

30-3/4(8) =

30 -6 = 24

his profit was $24

Step-by-step explanation:

5 0

3 years ago

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How to get a factor of a number

weeeeeb [17]

For instance, the factors<span> of 15 are 3 and 5, because 3×5 = 15. Some </span>numbers<span> have more than one factorization (more than one way of being factored). For instance, 12 can be factored as 1×12, 2×6, or 3×4. A </span>number<span> that can only be factored as 1 times itself is called "prime".</span>

3 0

3 years ago

98 POINTSSSSSS!!!!!!!!!

ddd [48]

Answer:

the answer is b -2u +w

or -2w - u

8 0

3 years ago

A box has a volume of 192 cubic inches, a length that is twice as long as its width, and a height that is 2 inches greater than

ruslelena [56]

Answer:

Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.

Step-by-step explanation:

Cuboid : A cuboid is a three dimension shape. The length ,breadth and height of a cuboid are not same.

A cuboid has 6 faces.
A cuboid contains 8 vertices.
A cuboid contains 12 edges .
The total surface area of a cuboid is

= 2(length×breadth+breadth×height+length×height) square units

The dimension of a cuboid is written as length×breadth×height.

The volume is( length×breadth×height) cubic units

Given that the volume of the box is 192 cubic inches.

Let x inches be the width of the cuboid.

Since the length is twice as long as its width.

Then length = 2x inches

Again height is 2 inches longer than width.

Then height = (x+2) inches.

Therefore the volume of the cuboid is

$=[x\times 2x\times (x+2)]$ cubic inches

$=[2x^2(x+2)]$ cubic inches

$=(2x^3+4x^2)$ cubic inches

According to the problem,

$2x^3+4x^2=192$

$\Rightarrow 2x^3+4x^2-192=0$

$\Rightarrow 2(x^3+2x^2-96)=0$

$\Rightarrow (x^3+2x^2-96)=0$

$\Rightarrow x^3-4x^2+6x^2-24x+24x-96=0$

$\Rightarrow x^2(x-4) +6x(x-4)+24(x-4)=0$

$\Rightarrow (x-4)(x^2+6x+24)=0$

Therefore x=4

Since the all zeros of x²+6x+24 =0 is negative.

Therefore breadth = 4 inches

length=(2×4) inches=8 inches

and height = (4+2)inches = 6 inches.

Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.

8 0

3 years ago

Easy question with 20 points

dsp73

Answer:

i got 195 because i rounded the numbers, but i believe the answer is D

3 0

3 years ago

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