1 km = 0.62 mi
1 mi = 1.6 km
80*0.62
-or-
60*1.6
Hope this helps
Answer:
The correct option is D.
Step-by-step explanation:
Let <em>x</em> denote the years.
The information provided is:
- The population of Metro City is 7420.
- The population is decreasing by 152 people per year.
- The population of Smallville is consistently 1200 less than half of Metro City.
From the provided data derive the equation for the population of Smallville <em>x</em> years after as follows:
![Y = [\frac{1}{2}\cdot (7420-152x)]-1200](https://tex.z-dn.net/?f=Y%20%3D%20%5B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%287420-152x%29%5D-1200)
The population of Smallville is 2282 after <em>x</em> years.
Compute the value of <em>x</em> as follows:
![2282= [\frac{1}{2}\cdot (7420-152x)]-1200](https://tex.z-dn.net/?f=2282%3D%20%5B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%287420-152x%29%5D-1200)
Thus, the time it will take for Smallville's population to reach 2282 is 3 years.
The correct option is D.
9514 1404 393
Answer:
72
Step-by-step explanation:
The triangles are said to be similar. (ΔNPQ ~ ΔRSQ) That means corresponding sides have the same ratio:
NP/RS = NQ/RQ = PQ/SQ = 24/32 = 21/28 = 3/4
This ratio, or scale factor, also applies to the perimeters of the two triangles.
perimeter NPQ / perimeter RSQ = 3/4
Using the given expressions for the perimeters, we have ...
(7x +2)/(10x -4) = 3/4
We can solve this equation in the usual way to find the value of x. Then we can use that value to find the perimeter of ΔNPQ.
4(7x +2) = 3(10x -4) . . . . . multiply both sides by 4(10x -4)
28x +8 = 30x -12 . . . . . eliminate parentheses
20 = 2x . . . . . . . . . . . add 12-28x to both sides
10 = x . . . . . . . . . . . divide both sides by 10
The perimeter of ΔNPQ is ...
7x +2 = 7(10) +2 = 72
The perimeter of triangle NPQ is 72 units.
Answer:
a. It would cost $77.50 to buy 5 tickets.
C(x)=17.5(5)-10
C(x)=87.50-10
C(x)=77.50
b. You can buy 8 tickets with $130
C(x)=17.5x-10
130=17.5x-10
Add 10 on both sides
140=17.5x
Divide 17.5 on both sides
8=x
Use the function from part a to estimate the fox population in the year 2006.round to the nearest fox
