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Aneli [31]
3 years ago
7

How do I find the complement?

Mathematics
1 answer:
likoan [24]3 years ago
6 0

Let A be some subset of a universal set U. The "complement of A" is the set of elements in U that do not belong to A.

For example, if U is the set of all integers {..., -2, -1, 0, 1, 2, ...} and A is the set of all positive integers {1, 2, 3, ...}, then the complement of A is the set {..., -2, -1, 0}.

Notice that the union of A and its complement make up the universal set U.

In this case,

U = {1, 2, 3, 6, 10, 13, 14, 16, 17}

The set {3, 10, 16} is a subset of U, since all three of its elements belong to U.

Then the complement of this set is all the elements of U that aren't in this set:

{1, 2, 6, 13, 14, 17}

You might be interested in
Find the distance between points M(-7,5) and Z(2,-3)
julsineya [31]

Hey there! I'm happy to help!

To find the distance between two points, you find the difference between the x values, square that, find the difference between the y values, square that, add the two numbers you got, and then find the square root.

We find the difference between the x values.

-7-2=-9

Square it.

-9²=81

We find the difference between the y-values.

5--3

5+3=8

We square it.

8²=64

We add the numbers we got.

81+64=145

We square root.

√145≈12.04

This formula comes from the Pythagorean Theorem! Now you can find the distance between any two points! Have a wonderful day! :D

8 0
4 years ago
Solve for x.<br> 2x2 + x = 10
Stells [14]

Answer:

x = 2, x = -5/2

Step-by-step explanation:

2x² + x - 10 = 0

(2x + 5)(x - 2) = 0

2x + 5 = 0

2x = -5

x = -5/2

x - 2 = 0

x = 2

8 0
3 years ago
Which expression is equivalent to one over threep + 15? one over three(p + 45) one over three(p + 5) 3(p + 45) 3(p + 5)
elena-s [515]

Answer:

\large\boxed{\dfrac{1}{3p+15}=\dfrac{1}{3(p+5)}}

Step-by-step explanation:

"one over threep + 15":

\dfrac{1}{3p+15}=\dfrac{1}{(3)(p)+(3)(5)}=\dfrac{1}{(3)(p+5)}=\dfrac{1}{3(p+5)}

5 0
3 years ago
Read 2 more answers
Solve the rational equation (3x^2+1)/(x-1) + x =4 + 4/(x-1)
natita [175]

Answer:

The answer to your question is letter D

Step-by-step explanation:

Rational equation

                               \frac{3x^{2} + 1}{x - 1} + x = 4 + \frac{4}{x - 1}

Simplify

                             \frac{3x^{2} + 1 + x(x - 1)}{x - 1} = \frac{4(x - 1) + 4}{x - 1}

Cancel the denominators and expand

                            3x² + 1 + x² - x = 4x - 4 + 4

Simplify                                              

                            4x² - x + 1 - 4x = 0

                            4x² - 5x + 1 = 0

Factor

                            4x² - 4x - 1x + 1 = 0

                            4x(x - 1) - 1(x - 1) = 0

                             (4x - 1)(x - 1) = 0

                            x₁ = 1/4        x₂ = 1

4 0
3 years ago
Find the magnitude of a vector with initial point A(3, 4, 10) and terminal point B(8, 4, –2).
Fantom [35]

Answer:

B

Step-by-step explanation:

Use the distance formula in 3 dimensions

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2+(z_{2}-z_{1})^2      }

with (x₁, y₁, z₁ ) = (3, 4, 10) and (x₂, y₂, z₂ ) = (8, 4, - 2)

d = \sqrt{(8-3)^2+(4-4)^2+(-2-10)^2}

   = \sqrt{5^2+0^2+(-12)^2}

    = \sqrt{25+144}

    = \sqrt{169}

     = 13 → B

4 0
3 years ago
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