Please help me i’m confused
1 answer:
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Answer:
a) Find the probability that the drink is less than 11.9 fluid ounces
We are supposed to find P(x<11.9)
x= 11.9
We will use z score formula :
Refer the z table
So, P(z<-0.67) = 0.2514
Hence the probability that the drink is less than 11.9 fluid ounces is 0.2514
b)Find the probability that the drink is between 11.6 and 11.9 fluid ounces
x= 11.6
We will use z score formula :
x= 11.9
We will use z score formula :
We are supposed to find P(11.6<x<11.9)
So, P(11.6<x<11.9)= P(x<11.9)-P(x<11.6)
P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)
Refer the z table
P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)
P(-1.67<z<-0.67)= 0.2514-0.0475
P(-1.67<z<-0.67)= 0.2039
So, the probability that the drink is between 11.6 and 11.9 fluid ounces is 0.2039.
c)Find the probability that the drink is more than 12.6 fluid ounces
We are supposed to find P(x>12.6)
x= 12.6
We will use z score formula :
Refer the z table
P(x>12.6)=1-P(x<12.6)
P(z>1.67)=1-P(z<1.67)
P(z>1.67)=1-0.9525
P(z>1.67)=0.0475
Hence the probability that the drink is more than 12.6 fluid ounces is 0.0475
d) Is the drink containing more than 12.6 fluid ounces an unusual event?
Since p value is less than alpha (0.05)
Answer = No, because the probability that a drink containing more than 12.6 fluid ounces is less than 0.05, this event is not unusual.
Answer:
(14, -2)
Step-by-step explanation:
To solve by using substitution, begin by solving for a variable in the first equation. Let's solve for x:
Now we know what <em>x</em> equals. Let's substitute this into the second equation:
We can then simplify:
Given equation
Combine y terms
Add 2
Divide by -11
So, we now know the value of y = -2.
To find the value of X, we can substitute the value of Y into one of the equations. Let's use the first one:
Substitute for y
Distribute 8
Add 16
So, we now know the value of x = 14.
Therefore, we know a solution to the system of equations is (14, -2).