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Vladimir [108]
4 years ago
6

Finding Side Lengths in a Right Triangle

Mathematics
1 answer:
velikii [3]4 years ago
7 0

Answer:

maybe it's 10.because c is 10,b is 10,and so as s.

hence s is 10 also.

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HELP ASAP! LOOK AT PIC PLS
ra1l [238]

Answer:

E

Step-by-step explanation:

well, yes we know what coins there are and that they’re in jars right? but to find which jar is worth the most, we need to know how many coins are in each. she could have 300 pennies, 2 quarters, 4 dimes, and 7 nickels. we need more information to answer this question so E is the only correct option!

6 0
3 years ago
The sum of two numbers is 108. the difference of the same numbers is 78. what are the numbers
Nimfa-mama [501]

The sum of two numbers:

x + y = 108

The difference of the same two numbers:

x - y = 78

We can use substitution to figure out x and y:

x - y = 78 can be changed to x = 78 + y

We can plug this into the first equation:

78 + y + y = 108

78 + 2y = 108

2y = 30

y = 15

Now solve for x using any of the two equations. I'll use the first equation since it's easier:

x + 15 = 108

x = 93

4 0
3 years ago
The lengths of three sides of a triangle are 2x, 3x-4, and x+4. Find a value of x that makes the triangle equilateral
Furkat [3]
Espero que no me jusgas por esto que estoy escribiendo
4 0
3 years ago
Please help me! Question is on image below.<br><br><br><br><br><br> Yo peeps Baby yoda is so cute!
Vedmedyk [2.9K]

Answer:

c = 26 cm

Step-by-step explanation:

using the Pythagorean theorem:

10² + 24² = c²

c² = 100 + 576  = 676

c = 26 cm

7 0
3 years ago
Find dy du , du dx , and dy dx .
dangina [55]

Answer:

a) \frac{dy}{du}=5(x^2 +1)^4, \frac{du}{dx}=2x, \frac{dy}{dx}=10x(x^2+1)^4  

b) \frac{dy}{du}=4(4x^2-x+6)^3, \frac{du}{dx}=8x-1, \frac{dy}{dx}=4(8x-1)(4x^2-2+6)^3  

Step-by-step explanation:

We can use the chain rule in the following form: is u=u(x) is a differentiable function depending on x and y=y(u) is a differentiable function depending on u, then \frac{dy}{dx}=\frac{dy}{du} \frac{du}{dx}.

a) \frac{dy}{du}=\frac{d}{du} (u^5)=5u^4=5(x^2 +1)^4 from the power rule.  

\frac{du}{dx}=\frac{d}{dx} (x^2 +1)=2x.

From the previous parts and the chain rule, \frac{dy}{dx}=\frac{dy}{du} \frac{du}{dx}=5(x^2 +1)^4(2x)=10x(x^2+1)^4  

b) \frac{dy}{du}=\frac{d}{du} (u^4)=4u^3=4(4x^2-x+6)^3  

\frac{du}{dx}=\frac{d}{dx} (4x^2-x+6)=8x-1 from the power and sum rules.

Then, \frac{dy}{dx}=\frac{dy}{du} \frac{du}{dx}=4(4x^2 -x+6)^3(8x-1)=4(8x-1)(4x^2-x+6)^3  

8 0
3 years ago
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