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Vladimir [108]
4 years ago
6

Finding Side Lengths in a Right Triangle

Mathematics
1 answer:
velikii [3]4 years ago
7 0

Answer:

maybe it's 10.because c is 10,b is 10,and so as s.

hence s is 10 also.

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Which expression is not equal to the number 0? Group of answer choices 5 - 5 -8 - (-8) 6 - (-6) -7 + 7
Sedbober [7]
6 - (-6)
This is because two negatives make a positive, so you’ll be adding 6+6 which equals to 12 not 0
3 0
3 years ago
-6×f (-3) -5×g(-7) =
polet [3.4K]

Answer:

=18fx+35gx

Step-by-step explanation:

I think.. Ask your teacher if it's right have a good day :)

4 0
3 years ago
Write two decimals that can be rounded to 2.5
zheka24 [161]
2.48 can be rounded pretty much any number between 2.45 to 2.5
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8 0
3 years ago
Read 2 more answers
A plant foreman wanted to know how many hours had been spent on a particular project. He asked his supervisors to report the hou
anygoal [31]

Answer:

828.7 hours.

Step-by-step explanation:

To answer a question in which the total time has to be calculated of all the activities, first of all, all the times have to be converted to a single form. There are two types: decimals and fractions. Convert the fractions into decimals.

Department A = 202.50 hours.

Department B = 212 3⁄4 hours  = 212.75 hours.

Department C = 198.25 hours.

Department D = 215 1⁄5 hours = 215.20 hours.

Therefore, the total number of hours spent on this project by all four departments. is the sum of all the above numbers. 202.50 hours + 212.75 hours + 198.25 hours + 215.20 hours = 828.7 hours.

Therefore, the total time is 828.7 hours!!!

3 0
3 years ago
Read 2 more answers
3x + ky = 8
sattari [20]

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

4 0
3 years ago
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