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My name is Ann [436]

3 years ago

7

Tuan is playing a game, but the spinner is incomplete. If the numbers in the sections of the spinner represent the probabilities

of spinning each section, help him figure out the fraction for the missing section of the spinner.
1/4,1/4,1/5

1 answer:

ioda3 years ago

8 0

The sum of the numbers should total to 1. Let us say that x is the missing number, therefore:

x + ¼ + ¼ + 1/5 = 1

x = 1 – ¼ - ¼ - 1/5

The numbers should have similar denominator:

x = 20/20 – 5/20 – 5/20 – 4/20

x = 6/20

<span>x = 3/10</span>

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The employee who created the chart made an error when computing the number of pounds of meat for one of the serving sizes .for w

lozanna [386]

Answer: b. 50

Step-by-step explanation:

Hence the employee made an error for 50 serving size.

4 0

4 years ago

What is the mean of the data set? {21, 23, 25, 25, 26, 28, 28, 28, 31, 33} 26.8 27 27.8 28

Lerok [7]

In mathematics, mean average means to take the sum of all the numbers and divide the sum by the number of elements in the set.

Add up the numbers.

<span>21 + 23 + 25 + 25 + 26 + 28 + 28 + 28 + 31 + 33 = 268

Divide by the number of elements in the set. Which is 10.

268 / 10 = 26.8

So, the answer to this question is 26.8</span>

8 0

4 years ago

Read 2 more answers

What is the median of this data set? Help NO links are you will be reported and NO fake answers for points. Thank you

Liono4ka [1.6K]

Answer:

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Step-by-step explanation:

4 0

3 years ago

Suppose that 5 cards are drawn from a well-shuffled deck of 52 cards. What is the probability that all 5 are not black?

lions [1.4K]

Here's the way I see it: 5 cards are drawn, one by one, without replacement. Half (or 26) of the original deck are black and half (26) are white.

P(5 are not black) = P(5 are red)

P(5 are not black) = P(first card is red) * P(second card is red) * P(third card is red)*P(fourth card is red)*P(fifth card is red) =

(26/52) * (25/51) * (24/50) * (23/49) * (22/48) = 0.025 (answer)

We start with 52 cards. We draw one, leaving 51 cards, 25 of which are red. And so on.

6 0

3 years ago

Solve the initial value problem y'=2 cos 2x/(3+2y),y(0)=−1 and determine where the solution attains its maximum value.

zloy xaker [14]

Answer:

$y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

$x={\pi}{4}$

Step-by-step explanation:

We are given that

$y'=\frac{2cos2x}{3+2y}$

y(0)=-1

$\frac{dy}{dx}=\frac{2cos2x}{3+2y}$

$(3+2y)dy=2cos2x dx$

Taking integration on both sides then we get

$\int (3+2y)dy=2\int cos 2xdx$

$3y+y^2=sin2x+C$

Using formula

$\int x^n=\frac{x^{n+1}}{n+1}+C$

$\int cosx dx=sinx$

Substitute x=0 and y=-1

$-3+1=sin0+C$

$-2=C$

$sin0=0$

Substitute the value of C

$y^2+3y=sin2x-2$

$y^2+3y-sin 2x+2=0$

$y=\frac{-3\pm\sqrt{(3)^2-4(1)(-sin2x+2)}}{2}$

By using quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$y=\frac{-3\pm\sqrt{9+4sin2x-8}}{2}=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

Hence, the solution $y=\frac{-3\pm\sqrt{4sin2x+1}}{2}$

When the solution is maximum then y'=0

$\frac{2cos2x}{3+2y}=0$

$2cos2x=0$

$cos2x=0$

$cos2x=cos\frac{\pi}{2}$

$cos\frac{\pi}{2}=0$

$2x=\frac{\pi}{2}$

$x=\frac{\pi}{4}$

3 0

3 years ago