Answer:
The largest possible value for the third side is 18.
Step-by-step explanation:
Here, the first side of the triangle = 17
Second side of the triangle = 2
Let us assume the third side of the triangle = m
Now, In any given triangle:
"Sum of any two sides of a triangle is strictly greater than the third side."
⇒ Sum of first side + Sum of second side > Third Side
or, m < 17 + 2
or, m < 19
hence, the largest possible value for m = 18
The base of this rectangle is 4
cm.
The height of this rectangle is 6
cm.
The area of this rectangle is 24
cm2.
First find the slope of the equation you are given
5x-4y=10
-4y=-5x+10
y=5/4x+10
So your slope is 5/4
Parallel lines have the same slope so the slope of line q is 5/4
Now use the point-slope formula to find the equation
y-(-7)=5/4(x-12)
y+7=5/4x-60/4
y+7=5/4x-15
y=5/4x-8
Line q’s equation is y=5/4x-8
Well 4/4 is equivalent to 1 so do 4/4+3/4
your answer would be 7/4