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mihalych1998 [28]
4 years ago
15

If point (4,5) is in the graph of a function, which equation must be true?

Mathematics
2 answers:
STALIN [3.7K]4 years ago
7 0

Answer:

Step-by-step explanation:

C) f(4)=5

Serjik [45]4 years ago
4 0
If (4,5) is a point on the graph of a function, then if x=4, f(x)=5. so f(4)=5.
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If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (u/v)(x)
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Answer:

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Step-by-step explanation:

Given: u (x) = x^5 - x^4 +x^2 and v(x) = -x^2

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Now plug in the given functions in the above formula, we get

= (x^5 - x^4 + x^2) / -x^2

We can factorize the numerator.

In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.

= x^2 (x^3 - x^2 + 1) / - x^2

Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.

(u/v)(x) = (x^3 - x^2 + 1) / -1

When we dividing the numerator by -1, we get

(u/v)(x) = -x^3 + x^2 - 1

Answer: c) -x^3 + x^2 - 1

Hope you will understand the concept.

Thank you.

6 0
4 years ago
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