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worty [1.4K]
3 years ago
11

Drag the boxes to match the answers

Mathematics
1 answer:
Alchen [17]3 years ago
8 0

Answer:

hi

Step-by-step explanation:

this is too hard for me but i am sure u will get it :D

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The points (4, 9) and (0, 0) fall on a particular line. What is its equation in slope-intercept form?
Nikolay [14]

Answer:

The equation of the line would be y = 4/9x

Step-by-step explanation:

In order to find the equation, we first need to find the slope. We can do this by using the slope equation with the points.

m(slope) = (y2 - y1)/(x2 - x1)

m = (9 - 0)/(4 - 0)

m = 9/4

Now that we have this, we can use point-slope form along with one of the points to get the equation.

y - y1 = m(x -x1)

y - 0 = 4/9(x - 0)

y = 4/9x

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Read 2 more answers
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
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