Answer:
a. E(x) = 3.730
b. c = 3.8475
c. 0.4308
Step-by-step explanation:
a.
Given
0 x < 3
F(x) = (x-3)/1.13, 3 < x < 4.13
1 x > 4.13
Calculating E(x)
First, we'll calculate the pdf, f(x).
f(x) is the derivative of F(x)
So, if F(x) = (x-3)/1.13
f(x) = F'(x) = 1/1.13, 3 < x < 4.13
E(x) is the integral of xf(x)
xf(x) = x * 1/1.3 = x/1.3
Integrating x/1.3
E(x) = x²/(2*1.13)
E(x) = x²/2.26 , 3 < x < 4.13
E(x) = (4.13²-3²)/2.16
E(x) = 3.730046296296296
E(x) = 3.730 (approximated)
b.
What is the value c such that P(X < c) = 0.75
First, we'll solve F(c)
F(c) = P(x<c)
F(c) = (c-3)/1.13= 0.75
c - 3 = 1.13 * 0.75
c - 3 = 0.8475
c = 3 + 0.8475
c = 3.8475
c.
What is the probability that X falls within 0.28 minutes of its mean?
Here we'll solve for
P(3.73 - 0.28 < X < 3.73 + 0.28)
= F(3.73 + 0.28) - F(3.73 + 0.28)
= 2*0.28/1.3 = 0.430769
= 0.4308 -- Approximated
The goal is not only to model the vector with 2 - D and to determine its important parameters, but also to examine the impact in the implementation. That is, Ogden's material parameters, element type, element size, and loading type.
Answer:
Range
Step-by-step explanation:
The range of a graph tells you <u>all of the possible y-values</u> for it.
There is also the domain, which tells you all of the possible x-values.
For example, if you have this relation, that only has these points:
(1, 2) (2, 4) (3, 6)
Then the range is {2, 4, 6}. This means the "y" can ONLY be the numbers stated here.
The domain would be {1, 2, 3}.
Answer: 14
Step-by-step explanation:
Input Data :
Point 1 (
x
A
,
y
A
) = (-4, -8)
Point 2 (
x
B
,
y
B
) = (10, -8)
Objective :
Find the distance between two given points on a line?
Formula :
Distance between two points = √
(x
B
−
x
A
)
2
+
(
y
B
−
y
A
)
2
Solution :
Distance between two points = √
(
10
− −
4
)
2
+
(
−
8
− −
8
)
2
= √
14
^2
+
0
^2
= √
196
+
0
= √
196
= 14
Distance between points (-4, -8) and (10, -8) is 14
