PLEASE HELP!!!! Write an inequality for the problem pleaseeeeee!!!!!????

a car travels at 54 km/h for first 20seconds , 36km/h for next 30seconds and finally 18km/h for next 10 seconds find the averade

Sladkaya [172]

Answer:

39 km/h

Step-by-step explanation:

Velocity is the rate of change of distance in a given direction with time. Mathematically,

Velocity = Displacement/time

Like speed, velocity is measured in Km/h or m/s.

Given that the car travels at 54 km/h for first 20seconds,

since 60 seconds = 1 minute and

60 minutes = 1 h,

20 seconds

= 20/(60 ×60) h

= 1/180 h

In the same vein,

30 seconds

= 30 / (60 ×60) h

= 1/120 h

10 seconds

= 10/(60 ×60) h

= 1/360 h

Hence if the car travels 54 km/h for 10 seconds, the distance covered

= 54 × 1/180

= 3/10 Km

If the car travels 36km/h for next 30seconds, the distance covered

= 36 × 1/120

= 3/10 Km

If the car travels 18km/h for next 10 seconds, the distance covered

= 18 × 1/360

= 1/20 km

Total distance = 3/10 Km + 3/10 Km + 1/20 Km

= 13/20 Km

Total time spent = 20 + 30 + 10

= 60 seconds

= 1/60 h

Average velocity = 13/20 km/ 1/60 h

= 39 Km/h

7 0

4 years ago

Please help solve!!<br> -5|x|+4=14

eduard

Answer:

2

Step-by-step explanation:

|x| means absolute value

|x| means if x is positive or negative, its still positive

-5|x|+4=14

-5|x|=10

|x|= -2

answer is 2

3 0

2 years ago

Read 2 more answers

two square regions have an area of 125 and 5 how many yards of fencing is needed to enclose? ( assume regions fenced separately)

nadya68 [22]

Answer:

$24\sqrt{5}\ yards$

Step-by-step explanation:

Let A1 be the area of one square and A2 be the area of second square

So,

A1 = s^2

where s is side of square

$s^2=125\\\sqrt{s^2}=\sqrt{125}\\s=\sqrt{25*5}\\ s= \sqrt{5^2 * 5}\\ s= 5\sqrt{5}$

So side of one square is $5\sqrt{5}$

To calculate the length of fence we need to find the perimeter of the square

So,

P1 = 4 * s

$=4*5\sqrt{5} \\=20\sqrt{5}$

For second square:

$A_2=s^2\\5=s^2\\\sqrt{s^2}=5\\{s}=\sqrt{5}$

The perimeter will be:

$P_2 = 4*s\\=4 * \sqrt{5} \\=4\sqrt{5}$

So the total fence will be: P1+P2

$= 20\sqrt{5}+4\sqrt{5} \\= 24\sqrt{5}\ yards$

3 0

3 years ago

Use the number line below. Which fraction is equivalent to

tankabanditka [31]

B easy simplify 3/6 and it’s 1/2 half of 6 is 3 so B is the answer

3 0

3 years ago

Read 2 more answers

Loc can mow his entire lawn in 20 minutes; Loc's roommate Reza needs 30 minutes to mow the entire lawn. If Loc starts mowing at

ycow [4]

Loc and Reza together will finish the entire mowing process on the lawn at 1:14 p.m.

<h2>Calculation of total mowing time taken</h2>

Loc mow the total area in 20 mins.

So, his pace is 1 lawn / 20 minutes or 1/20th of a lawn each minute.

Reza's pace is 1 lawn / 30 minutes, or 1/30th of a lawn each minute because he can mow the grass in that amount of time.

Reza joins Loc after he has been mowing for 5 minutes. He can mow 1/20th of the grass in these 5 minutes, which is 5/20th of the lawn =1/4th lawn

There is currently just

1-1/4=3/4 of the lawn left to complete.

We may construct the following equation by assuming that they mow together for x mins:

1/20x + 1/30x = 3/4 [amount done by Loc + Reza = total amount]

⇒(3x+2x)/60x = 3/4

⇒5x/60 = 3/4

⇒x/12= 3/4

⇒4x=36

⇒x= 9 mins

So, when they collaborate, they can complete the lawn in 9 minutes.

Hence, Loc mows alone for 9+5 mins = 14 mins

Therefore, it is concluded that starting at 1 p.m they finish the mowing at 1:14 p.m.

Learn more about the mow-related problems here:

brainly.com/question/2564050

#SPJ4

5 0

2 years ago