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4 years ago

Question and examples in picture. Please help

Mathematics

1 answer:

kondor19780726 [428]4 years ago

3 0

Answer:

$a = 7, LN = 105$

Step-by-step explanation:

$LM = 8a$

$\textrm{LM also equals 56}$

Solve for a

$8a = 56 \rightarrow a =7$

Given that a = 7, solve for MN

$MN = 7a$

$MN = 7(7) \rightarrow 49$

In order to find LN, add 49 and 56 together

$49 + 56 = 105$

$LN = 105$

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Nirmala graphed the relationship between the duration (in hours) of using an oil lamp and the volume (in milliliters) of oil rem

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Answer:

Nirmala can use the lamp for 31.66 hours before it runs out of oil.

Step-by-step explanation:

From the graph,

Take any two points, let say

(15, 25)

(25, 10)

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(15,\:25\right),\:\left(x_2,\:y_2\right)=\left(25,\:10\right)$

$m=\frac{10-25}{25-15}$

$m=-\frac{3}{2}$

The equation of line in slope-intercept form

$y = mx + b$

Putting $m=-\frac{3}{2}$ and any point, let say (25, 10), to find the y-intercept 'b'

$10=-\frac{3}{2}\left(25\right)+b$

$-\frac{3}{2}\left(25\right)+b=10$

$-\frac{75}{2}+b=10$

$\mathrm{Add\:}\frac{75}{2}\mathrm{\:to\:both\:sides}$

$-\frac{75}{2}+b+\frac{75}{2}=10+\frac{75}{2}$

$b=\frac{95}{2}$

$b=47.5$

So the equation of line will be:

$y = mx + b$

$y=-\frac{3}{2}x+47.5$

In order to find how long Nirmala can use the lamp before it runs out of oil, we need to find x-intercept which can be obtained by putting y = 0, and solve for x, as duration lies on x-axis.

$y=-\frac{3}{2}x+47.5$

Putting y = 0

$0=-\frac{3}{2}x+47.5$

$-\frac{3}{2}x+47.5=0$

$-\frac{3}{2}x=-47.5$

$\mathrm{Multiply\:both\:sides\:by\:}2$

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$\mathrm{Divide\:both\:sides\:by\:}-3$

$\frac{-3x}{-3}=\frac{-95}{-3}$

$x=\frac{95}{3}$

$x=31.66$

Therefore, Nirmala can use the lamp for 31.66 hours before it runs out of oil.

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