Y = 2^x and y = log₂x
Exponents and logs (to the same base = 2) are inverses of each other.
All inverse functions are symmetric about line y = x
y = log₂x is NOT the logarithmic form of y = 2^x
The logarithmic form of y = 2^x is x = log₂y (NOT y = log₂x)
Answer: A, C
I think it's C. drawing a king from a deck
Answer:

Step-by-step explanation:
we are given a function

we would like to simplify it for h(-1)
in order to do so
substitute the value of x

by order of PEMDAS
simplify square:

simplify multiplication:

simplify addition:

simplify subtraction:

reduce fraction:

Around 90% of the time, you'll get joke answers or answers from bots. Even if I report their answers, they will report my question back? Even though their answers are completely irrelevant to my questions? Also, your moderators are probably 12 years olds, because why? THEY. DELETE. EVERY. CORRECT. ANSWER. I. MADE. Not to mention, that there are a bunch of other users that started grouping and bullied me with vulgar words. Disgusting. Is this what your moderating has become, Huh? Brainly? IS THIS WHAT YOU CALL A PEACEFUL FRIENDLY WEBSITE FOR EVERYONE? Shame on you, I will not use this website again, until you fix your moderation "ENTIRELY".