The question is incomplete, as the depth of the hook isn't given in the question. However, using a proposed depth for the hook, we could give a stepwise solution to the exercise.
Answer:
Kindly check explanation
Step-by-step explanation:
If given a hook depth of 6 meters, and a distance of 8 m(fishing line from hook) at the the Same depth, then the distance between rose and the fish, x can be calculated, using the relation.
Hypotenus² = opposite² + adjacent²
(refer to attached picture)
x² = 6² + 8²
x² = 36 +. 64
x² = 100
x = sqrt(100)
x = 10 meters
You can use the actual depth value to obtain the actual solution to your question.
Answer:

Step-by-step explanation:
<em><u>The formula for finding the area of a triangle is:</u></em>
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<em><u>The "b," is the base (7), and the "h," is the height (8):</u></em>


28
Answer:
2 to the power of one sixth
Step-by-step explanation:
Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:
![\sqrt[n]{x} = {x}^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D%20)
So you can rewrite the given fraction as

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

Since

the answer is
![{2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B%20%5Cfrac%7B1%7D%7B6%7D%20%7D%20%20%5C%3A%20or%20%5C%3A%20%20%5Csqrt%5B6%5D%7B2%7D%20)
Answer:dfdasfsdafdasfdasfdasfdasfdsafdasfdasfdasfdasfdasfdsafasfdas
Step-by-step explanation:dsgdasjghdasfkjhdasfjhasdfjdaskfhasfkjdhasfkljhdasfkjhdskjahfdkjsahfkljdashfkjdsahfkjdashfkjdhsafdhsfkjdhsfkljdhfkjdhasfkljdashfkljdsahfkjdshfkljds
Answer:
There could be many, my estimate would be around 100.
Step-by-step explanation:
It may sound exaggerated but it can be.