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Nadya [2.5K]
3 years ago
12

What is y when x is equal to 10 in 10x+y=19

Mathematics
1 answer:
Maurinko [17]3 years ago
4 0
<span>10x+y=19

when x = 10:

substitute with x=10 into the equation given:

10(10) + y = 19

or:

100 + y = 19

bring 100 to the other side to be -100

y = 19 - 100

y = -81


That's it
</span>
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Determine the simple interest that is<br> accured on $.5500 for five years at<br> a rate of 8.5%.
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$2337.5

Step-by-step explanation:

5500x5x8.5/100

=$2337.5

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A company loses $5,400 as the result of a manufacturing defect. The 8 owners of the company must share the loss equally. What is
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Change in profit = x - (5,400/8)
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Identify the center and the radius of each.<br><br> x^+y^+26x-22y+281=0
inessss [21]

Answer:

Center (-13,11) , radius 3

Step-by-step explanation:

The given circle has equation

x^2+y^2+26x-22y+281=0

We compare this to the general equation.

x^2+y^2+2ax+2by+c=0

where (-a,-b) is the center.

This implies that;

2a=26

\Rightarrow a=13

2b=-22

b=-11

The center is therefore (-13,11)

The radius is given by

r=\sqrt{a^2+b^2-c}

r=\sqrt{13^2+(-11)^2-281}

r=\sqrt{9}

The radius is 3

3 0
3 years ago
one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt
In-s [12.5K]

Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

 \text{The population of country A that admit they are from B} = \frac{1}{3}\text{ of }A

⇒ \text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A

= \frac{3-1}{3} A

= \frac{2}{3} A

\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B

⇒ \text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B

But, Again according to the question,

The total population that claims that they are from A =  one half of the total population of A and B.

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B

⇒ \frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B

⇒ \frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B

⇒ \frac{1}{6} A = \frac{1}{4} B

⇒ A =\frac{6}{4}B

⇒ \frac{A}{B} =\frac{3}{2}

8 0
3 years ago
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