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Alexus [3.1K]
3 years ago
8

What is the volume of a frustum of a rectangular pyramid if one base has measurements 6 ft. × 8 ft., the other base has measurem

ents 14 ft. × 18 ft., and the height is 3 ft.?
    
A. 252.8 ft.3
B. 120.98 ft.3
C. 409.98 ft.3
D. 560.30 ft.3
Mathematics
2 answers:
RoseWind [281]3 years ago
7 0
To solve this, we use the formula for the volume of the frustum of a cone which is expressed as:

<span>V= (H/6)[WL + (W+a)(L+b) + ab]
</span>V = 3/6 [(6 ft. × 8 ft.) + (6 + 14)(18 + 8) + (<span>14 ft. × 18 ft.)]
</span>V = 409.98 ft^3 <-----OPTION C 
Anna11 [10]3 years ago
4 0
Hello there.

<span>What is the volume of a frustum of a rectangular pyramid if one base has measurements 6 ft. × 8 ft., the other base has measurements 14 ft. × 18 ft., and the height is 3 ft.? 

</span><span>C. 409.98 ft.3
</span>
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Ludmilka [50]
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Find the limit of the function by using direct substitution.
serg [7]

Answer:

Option a.

\lim_{x \to \frac{\pi}{2}}(3e)^{xcosx}=1

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You have the following limit:

\lim_{x \to \frac{\pi}{2}{(3e)^{xcosx}

The method of direct substitution consists of substituting the value of \frac{\pi}{2} in the function and simplifying the expression obtained.

We then use this method to solve the limit by doing x=\frac{\pi}{2}

Therefore:

\lim_{x \to \frac{\pi}{2}}{(3e)^{xcosx} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})}

cos(\frac{\pi}{2})=0\\

By definition, any number raised to exponent 0 is equal to 1

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\lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}cos(\frac{\pi}{2})} = \lim_{x\to \frac{\pi}{2}}{(3e)^{\frac{\pi}{2}(0)}\\\\

\lim_{x\to \frac{\pi}{2}}{(3e)^{0}} = 1

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\lim_{x \to \frac{\pi}{2}}(3e)^{xcosx}=1

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3 years ago
Estimate 200,629 +28,542
Alinara [238K]
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5 0
3 years ago
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