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2 years ago

Using the quadratic formula to solve 5x=6x square-3, what are the values of x

Mathematics

1 answer:

hammer [34]2 years ago

3 0

Step-by-step explanation:

$5x = {6x}^{2} - 3$

$3 = 6x^{2} - 5x$

$0 = {6x}^{2} - 5x - 3$

${6x}^{2} - 5x - 3 = 0$

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Nadusha1986 [10]

Answer:

yes they are similar

step 1: flip it across the y-axis

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Step-by-step explanation:

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3 years ago

What is the area of the regular polygon?

BartSMP [9]

Answer:

You could use the polygon area formula OR here's an easier solution

We draw the lines DC and DE

Angle ADC = 120°

Triangle ADC is a 30 60 90 triangle

In such a triangle Line AE = hypotenuse * sq root (3) /2

Line AE = 3 * 0.8660254038 = 2.5980762114

Line DE = 1.5

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Step-by-step explanation:

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2 years ago

We went on a road trip and drove 70 miles per hour.If we continued at this speed,how long would it take us to drive 420 miles.sh

jonny [76]

Answer:

6 hours

Step-by-step explanation:

420 ÷ 70 = 6. Divide the distance and speed to get the amount of time.

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3 years ago

What would be the exact side length of a square with the area of 8 m2

Paraphin [41]

Answer:

2*square root of 2

Step-by-step explanation:

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3 years ago

I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

Perfect squares: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately before and after 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.

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1 year ago

Read 2 more answers