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Mazyrski [523]
3 years ago
11

Using the quadratic formula to solve 5x=6x square-3, what are the values of x

Mathematics
1 answer:
hammer [34]3 years ago
3 0

Step-by-step explanation:

5x =  {6x}^{2}  - 3

3 = 6x^{2} - 5x

0 =  {6x}^{2} - 5x - 3

{6x}^{2} - 5x - 3 = 0

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What values of x and y satisfy x + 2y = 6 and 2x + 3y = 4 simultaneously?
jeka94
First take x + 2y = 6 and isolate x:
x = 6 - 2y
Then substitute that for x in 2x + 3y = 4:
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4 0
3 years ago
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Por Favor! Alguém me ajuda.
Nutka1998 [239]

Answer:

The answer is A.

Step-by-step explanation:

You have to apply :

{(a  -  b)}^{2} ⇒ {a}^{2}   -  2ab +  {b}^{2}

So for this question :

{(3a - b)}^{2}

=  {(3a)}^{2}  - 2(3a)(b) +  {(b)}^{2}

= 9 {a}^{2}  - 6ab +  {b}^{2}

8 0
4 years ago
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