∛(2x + 5) - 3 = 0
Add 3 to both sides
∛(2x + 5) = 3
Cube both sides
2x + 5 = 27
Subtract 5 from both sides
2x = 22
Divide both sides by 2
x=11
There's your answer. Have an awesome day! :)
Answer:
In Section 6.1, we introduced the logarithmic functions as inverses of exponential functions and
discussed a few of their functional properties from that perspective. In this section, we explore
the algebraic properties of logarithms. Historically, these have played a huge role in the scientific
development of our society since, among other things, they were used to develop analog computing
devices called slide rules which enabled scientists and engineers to perform accurate calculations
leading to such things as space travel and the moon landing. As we shall see shortly, logs inherit
analogs of all of the properties of exponents you learned in Elementary and Intermediate Algebra.
We first extract two properties from Theorem 6.2 to remind us of the definition of a logarithm as
the inverse of an exponential function.
Step-by-step explanation:
Hope this helps
Answer:
Hey buddy whatsup? All good
Coming to the question fig 1 and 3 aren't functions
Coz.... Reason for fig 1... Every distinct element of domain must have a unique element in codomain, but in this fig the same element has more than two unique elements which is a relation not a function.
Reason for fig 3 every element in domain must have an unique element in codomain but in this fig the element c doesn't have any unique element hence it isn't a function.....
Thank you
Answer:
<h2>a³-b³ = (a-b)(a²+ab+b²)</h2>
Step-by-step explanation:
let the two perfect cubes be a³ and b³. Factring the difference of these two perfect cubes we have;
a³ - b³
First we need to factorize (a-b)³
(a-b)³ = (a-b) (a-b)²
(a-b)³ = (a-b)(a²-2ab+b²)
(a-b)³ = a³-2a²b+ab²-a²b+2ab²-b³
(a-b)³ = a³-b³-2a²b-a²b+ab²+2ab²
(a-b)³ = a³-b³ - 3a²b+3ab²
(a-b)³ = (a³-b³) -3ab(a-b)
Then we will make a³-b³ the subject of the formula from the resultinh equation;
a³-b³ = (a-b)³+ 3ab(a-b)
a³-b³ = a-b{(a-b)²+3ab}
a³-b³ = a-b{a²+b²-2ab+3ab}
a³-b³ = (a-b)(a²+b²+ab)
a³-b³ = (a-b)(a²+ab+b²)
The long division problem that can be used is (a-b)(a²+ab+b²)
Answer: idk
Step-by-step explanation: i
d
k
, such that s is the length of any side. You are given that the volume of the carton is 1000 cubic inches, because each 1 by 1 by 1 cube has a volume of one cubic inch. If you put your given v into the equation, you get 
. If you take the cube root of both sides, you get that s=10 because 10^3=1000