Finding the Bearing<span> of a </span>Ship<span>
Example : A </span>ship<span> leaves the port of Miami with a </span>bearing<span> of S80◦E and a </span>speed<span> of. 15 knots. After 1 hour, the </span>ship<span> turns 90◦ toward the south.</span>
Answer:
y=x-2
Step-by-step explanation:
This slope goes through the point and is perpendicular to y=-13x+1
Hope this helped
Answer:
y - 6 = 3(x + 2)
Step-by-step explanation:
Point-slope form: y - y1 = m(x - x1)
Given: m(slope) = 3, (6, -2)
(x1, y1) = (6, -2)
Input the given values of the slope and the point into the equation for point-slope form:
y - (-2) = 3(x - 6)
y + 2 = 3(x - 6)
The equation written in point-slope form is: y + 2 = 3(x - 6)
You find the eigenvalues of a matrix A by following these steps:
- Compute the matrix
, where I is the identity matrix (1s on the diagonal, 0s elsewhere) - Compute the determinant of A'
- Set the determinant of A' equal to zero and solve for lambda.
So, in this case, we have
![A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-2%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%5Cimplies%20A%27%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-2%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Clambda%260%5C%5C0%26%5Clambda%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1-%5Clambda%26-2%5C%5C-2%26-%5Clambda%5Cend%7Barray%7D%5Cright%5D)
The determinant of this matrix is
Finally, we have
So, the two eigenvalues are
