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3 years ago

7

the legs of a right triangle measure 5 inches and 7 inches if the theta is the the angle between the 5 inch leg and hypotenuse,

sin theta

1 answer:

Goryan [66]3 years ago

7 0

First find the hypotenuse.

a^2 + b^2 = c^2

5^2 + 7^2 = c^2

c^2 = 25 + 49

c = sqrt(74)

sin(theta) = opp/hyp

sin(theta) = 7/(sqrt(74))

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Problem 1:

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STATEMENT REASON

1. <NMQ ≅ <NPQ Any point on a <em>perpendicular bisector</em>

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2. NQ ⊥ MP Definition of a<u> line</u>.

3. MQ ≅ PQ <em>Equal segments</em> of a bisected <u>line</u>.

4. MN ≅ PN Any point on a <em>perpendicular bisector </em>

is at the same <u>distance</u> to the

two ends of the <em>line segment</em>.

5. <MNQ ≅ <PNQ <u>Equal</u> measure of the <u>bisected</u> angle.

Problem 2:

A line <em>segment</em> is the shortest <u>distance</u> between two points.

STATEMENTS REASONS

1. m<PSR ≅ m<PSQ A <em>perpendicular bisector </em>is always at a right

angle to the <u>bisected</u> <em>line segment</em>.

2. m<RPS ≅ m<QPS Equal measure of the <u>bisected</u> <em>angle</em>.

3. RS ≅ QS Property of a <u>bisected</u> <em>line</em> segment.

4. PR ≅ PQ Any point on a <em>perpendicular bisector </em>

is at the same <u>distance</u> to the two ends of

the <u>line</u> segment.

For more clarifications on the perpendicular bisector of a line segment, visit: brainly.com/question/12475568

#SPJ1

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