The area of the trapezoid is x+11 cm.
Given a trapezoid has one side of (x+6) cm, the other side is 5 cm, and the height is 2 cm.
A two-dimensional quadrilateral consisting of the sum of non-adjacent parallel sides and a suitable non-parallel side is denoted as a trapezoid.
Now we will use the formula to find the area of a trapezoid
Area = 1/2 × (base 1 + base 2) × height
Here base 1 = (x+6) cm, base 2 = 5cm and height = 2cm
Substituting the values into the formula, we get
Area = 1/2 × (x+6+5) × 2
Area = 1/2 × (x+11) × 2
Area = x+11
Thus, the area of the given figure when one side is x+6, the other side is 5 cm and the height is 2 cm is x+11 cm.
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Answer:
undefined/no solution
Step-by-step explanation:
you use elimination to solve. So multiply 2x+4y=-12 by 1 and x+2y=-2 by 2. then you subtract 2x+4y=-12 by 2x+4y=-4 and get 0y=-8. Anything divided by 0 is undefined/no solution because you can't divide anything by 0.
Answer:
The weight corresponding to which weight will be larger than 14% of times equals 427.635 grams.
Step-by-step explanation:
We need to find the value of weight that corresponds to 14% of area under the normal distribution curve
It is given that
Using standard normal distribution tables we find value of Z corresponding to 14% of the area as -1.080
Thus using the standard equation
$11.25/2.24 lb = $5.02/lb
Answer:
2
Step-by-step explanation:
