The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
Read more about exponential functions at:
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Answer:
y = 3/2x - 5
Step-by-step explanation:
To find the equation of the line
Step 1: find slope
( 2 , -2) ( 4 , 1)
x_1 = 2
y_1 = -2
x_2 = 4
y_2 = 1
Insert the values into
m = (y_2 - y_1) / (x_2 - x_1)
m = ( 1 - (-2) / (4 - 2)
= ( 1 + 2) / ( 4 -2 )
= 3 / 2
m = 3/2
Step 2: substitute m into the equation
y = mx + c
y = 3/2x + c
Step 3: substitute any of the two points into the equation
Let's pick (4 , 1)
x = 4
y = 1
y = 3/2x + c
1 = 3/2(4) + c
1 = 3*4/2 + c
1 = 12/2 + c
1 = 6 + c
1 - 6 = c
c = 1 - 6
c = -5
Step 4 : substitute c into the equation
y = 3/2x + c
y = 3/2x - 5
The equation of the line is
y = 3/2x - 5
Answer: 4h/5
Step-by-step explanation:
Step-by-step explanation:
12+6x-9+4
6x+7
option B
