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2 years ago

Find the equation for the circle with center (-2,4) and passing through (-1,- 4).

Mathematics

1 answer:

LuckyWell [14K]2 years ago

8 0

Answer:

(x+2)^2 + (y-4)^2 = 65

Step-by-step explanation:

r^2 = (4-(-4))^2 + (-1-(-2))^2 = 65

center = (-2, 4) so you add 2 to x and subtract 4 from y

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Liam's breakfast was an egg and cheese biscuit with a carton of milk. He spent a total of $5.65. Finn spent $7.65 on an egg and

ruslelena [56]

Answer:

An egg and cheese biscuit was $3.65.

Step-by-step explanation:

Liam's breakfast was:

$P = E + C + M$

Where:

P: total price

E: egg

C: cheese biscuit

M: carton of milk

$P = E + C + M$

$5.65 = E + C + M$ (1)

Now, Finn's breakfast was:

$P = E + C + 2*M$

$7.65 = E + C + 2*M$ (2)

By subtracting equation (2) from (1) we have:

$7.65 - 5.65 = 2M - M$

$M = 2$

Hence, the price of a carton of milk is $2, so by entering this value into equation (1) we can find the price of an egg and cheese biscuit:

$5.65 = E + C + M$

$5.65 - 2 = E + C$

$E + C = 3.65$

Therefore, an egg and cheese biscuit was $3.65.

I hope it helps you!

7 0

2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

2 years ago

Subtract 15 and 4 , double the difference, and then add two-thirds

mrs_skeptik [129]

15-4 = 11

11 x 2 = 22

22 + 2/3 = 68/3

3 0

3 years ago

Read 2 more answers

How to expand and simplify this equation 7(2a+3)+3(4a-2).

Pavel [41]

Ok, so first we distribute, you multiply the seven into everything in the parentheses next to it. So far we have, 14a+21+3(4a-2). You distribute the three into the parentheses to get, 14a+21+12a-6. You combine the like terms to get, 26a-15. You cannot simplify it any further so the answer is 26a-15.

8 0

2 years ago

Read 2 more answers

What times 5 equals 70?

Viefleur [7K]

5n =70
5 x 14 = 70
hope this helped :)

3 0

3 years ago

Read 2 more answers