2 years ago

What are two factors of 44 that add to 7?

Mathematics

2 answers:

Vikki [24]2 years ago

7 0

Factors of 44 that add up to 7 = 1 + 2 + 4

erastovalidia [21]2 years ago

3 0

Well I'm going to assume you mean -44

If you want them to add to 7, they are -4 and 11
If you want them to add to -7, they are -11 and 4

You might be interested in

There are 68 calories in 1 serving of cereal. If a bowl holds 7 servings, how many calories are in the bowl?

maria [59]

Answer:

476

Step-by-step explanation:

$68 \times 7 = 476$

because there are 68calories per serving and there are 7 servings

6 0

3 years ago

What is the product of −3/11 and <br> −2/15?

Dafna11 [192]

Multiply -3/11 and -2/15 straight across

-3(-2) = 6
11(15) = 165

6/165 is your product, or 0.036 (rounded)

hope this helps

5 0

3 years ago

Read 2 more answers

Worldwide, the proportion of babies who are boys is about 0.51 . Let the random variable X represent the number of boys in five

solmaris [256]

Answer:

mean = 2.55

Standard deviation = 1.118

Step-by-step explanation:

Probability of babies who are boys

P = 0.51

Then we have q = 1-p

= 1-0.51

= 0.49

We have n = 5

We calculate the mean as:

= 0.51x5

= 2.55

Therefore mean = 2.55

The standard deviation

= √variance

= √npq

= √0.51x5x0.49

=√1.2495

= 1.118

6 0

2 years ago

To transport 228 people to an island island ferry make six different trips on each trip the ferry carries the same number of peo

Tju [1.3M]

240 I calculated it your welcome :)

3 0

3 years ago

Read 2 more answers

One variable examined is the survival rate 10 years after tagging. The scientists observed that 10 of the 50 metal tagged pengui

Oksana_A [137]

Answer: 90% confidence interval would be $(-0.2483,-0.0717)$

Step-by-step explanation:

Since we have given that

n₁ = 50

Number of metal tagged penguins survived = 10

So, $p_m=\dfrac{10}{50}=0.2$

n₂ = 50

Number of electronic tagged penguins = 18

So, $p_e=\dfrac{18}{50}=0.36$

So, at 90% confidence interval, z = 1.28

So, interval would be

$(p_m-p_e)\pm z\sqrt{\dfrac{p_m(1-p_m)}{n}+\dfrac{p_e(1-p_e)}{n}}\\\\=(0.2-0.36)\pm 1.28\sqrt{\dfrac{0.2\times 0.8}{50}+\dfrac{0.36\times 0.64}{50}}\\\\=-0.16\pm 0.0883\\\\=(-0.16-0.0883,-0.16+0.0883)\\\\=(-0.2483,-0.0717)$

Hence, 90% confidence interval would be

$(-0.2483,-0.0717)$

6 0

3 years ago