Ask question

Ask question

All categories

3 years ago

14

Ramon earns $1,690 each month and pays $53.60 on electricity. To the nearest tenth of a percent, what percent of Ramon's earning

s are spent on electricity each month?

1 answer:

coldgirl [10]3 years ago

8 0

Answer:

3.1%

Step-by-step explanation:

divide his electricty payment by his monthly pay

You might be interested in

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

What is 26 divided by 45702

irinina [24]

The answer is
0.000568902892652.

4 0

3 years ago

How do you write 10% as a fraction or mixed number in simplest form?

Harman [31]

1/10 in fraction from or 0.1 in decimal form

7 0

3 years ago

Read 2 more answers

While solving the

kvv77 [185]

Answer:

Multiplication of Alzebra

method has been used by Natalie

8 0

3 years ago

Read 2 more answers

Please answer the question in the picture

Len [333]

Reorder terms so constants are on the left

(3x + 7) 8x^2
8(3x +7)x^2

Distribute

Answer: 24x^3+56x^2

6 0

3 years ago