The easiest way to find such limits, where there is a numerator and a denominator is to apply <span><span>Hospital's Rule. 1st find the derivative of the numerator and the derivative of the denominator, if it still gives an indeterminate value, find the second derivative of N and D
3) lim sin(2x)/x when x →0 Derivative sin2x → 2cos2x Derivative x→ 1 2cos2x/1 when x→0 , 2cos2x → 2 and lim sin(2x)/x when x →0 is 2
4) lim(sinx)/(2x²-x)
→cosx/(2x-1) when x →0 cosx/(2x-1) = -1 and lim(sinx)/(2x²-x) when x →0 is -1
and so on and so forth. Try to continue following the same principle
