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pochemuha
3 years ago
8

I need help on 3,4,5,6,7,8 if you can show me the steps

Advanced Placement (AP)
1 answer:
serious [3.7K]3 years ago
6 0
The easiest way to find such limits, where there is a numerator and a denominator is to apply <span><span>Hospital's Rule.
1st find the derivative of the numerator and the derivative of the denominator, if it still gives an indeterminate value, find the second derivative of N and D

3) lim sin(2x)/x when x →0
 Derivative sin2x → 2cos2x
 Derivative x→ 1
 2cos2x/1 when x→0 , 2cos2x → 2
 and lim sin(2x)/x when x →0 is 2

4) lim(sinx)/(2x²-x)

→cosx/(2x-1) when x →0 cosx/(2x-1) = -1
and lim(sinx)/(2x²-x) when x →0 is -1

and so on and so forth. Try to continue following the same principle


</span></span>
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