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jonny [76]
3 years ago
8

Hellpppo guys pleaseeeee

Mathematics
1 answer:
AURORKA [14]3 years ago
5 0
D for sure hope it helps 


plz give brainliest
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In the June 2007 issue, Consumer Reports also examined the relative merits of top-loading and front-loading washing machines, te
saveliy_v [14]

Answer:

Yes

Step-by-step explanation:

Given that in the June 2007 issue, Consumer Reports also examined the relative merits of top-loading and front-loading washing machines, testing samples of several different brands of each type.

The difference in mean values test gave a p value of 0.32

Confidence level = 95%

Alpha = 1-0.95 = 0.05

Compare p with alpha, here p >alpha

Hence we accept null hypothesis that there is no difference in the means.

Confidence interval method also will yield the same result.  i.e. confidence interval for difference of means would definitely contain 0 at 95% conf level.

So answer is yes

3 0
3 years ago
PLZ HELP ME ASAP!!!!!!!!
soldier1979 [14.2K]

THINK AND RELAX TAKE A DEEP BREATH

3 0
3 years ago
Pre-Cal<br> Complete the equation so that it has solutions of -5 and 7.
Phoenix [80]
-2, -35 and just use the dolling formula they give you.
4 0
3 years ago
The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c
Slav-nsk [51]

\text{Answer} : \text{The expected value of a t-shirt is \$31.}

Explanation:

Since we have given that

The prices of three t-shirts styles  i.e $24, $30, $36 with their probability is given by

\frac{1}{6}, \frac{1}{2},\frac{1}{3}

As we know that,

E(X)= \sum_{1}^{3}x_iP(x_i)

\text{where} x_i \text{ is the prices of t- shirts styles}

Now,

x_1= \$24 , x_2=\$30 , x_3=$36

and

P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}

So,

E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31

So, the expected value of a t-shirt = $31.

4 0
3 years ago
The population of the United States was about 280 million in 2000 and about 310 million in 2010 . What was the annual rate of ch
storchak [24]
<span>In order to solve this you would need to take the difference in population and then divide by the difference of the number of years that have passed. So first we figure that there is a 30 million difference in population over the course of 10 years. So you would take 30 and divide by 10. Your problem would then appear as this 30/10=3 ... ( I removed all unnecessary zeros from the equation to simplify it). The answer is an annual rate of 3 million people per year (after adding back all necessary zeros to get back to the proper population number in the millions).</span>
7 0
3 years ago
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