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scZoUnD [109]
3 years ago
10

Solve n³ + 2n² - 15n = 0 by factoring. Show the factored form of the equation, and the resulting solutions.

Mathematics
2 answers:
Semenov [28]3 years ago
5 0

Answer: n = 0

n = 3

n = - 5

Step-by-step explanation:

The given cubic equation is expressed as

n³ + 2n² - 15n = 0

Since n is common to each term, we would factorize n out. It becomes

n(n² + 2n - 15) = 0

n = 0 or

n² + 2n - 15 = 0

To further factorize the quadratic equation, we would would find two numbers such that their sum or difference is 2n and their product is - 15n². The two numbers are 5n and - 3n. Therefore,

n² + 5n - 3n - 15 = 0

n(n + 5) - 3(n + 5) = 0

(n - 3)(n + 5) = 0

n = 3 or n = - 5

laila [671]3 years ago
4 0

Step-by-step explanation:

Take n common

n(n²+2n-15)=0

now factorise the quadratic one as n when goes to RHS it becomes zero

n²-3n+5n-15=0

n(n-3)+5(n-3)=0

n=3,-5

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X 0 1 2 3

P(x) .21 .35 .25 .17

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5 0
3 years ago
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TEA [102]
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6 0
3 years ago
Subtract. Fill in the missing numbers. 11-4=? 4=3+1 So, 11-4=
Deffense [45]

Answer:

7

Step-by-step explanation:

7 0
3 years ago
50 points! I understand A. and B. but I would really appreciate help with C.
FromTheMoon [43]

Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

P(t)=6.10t^2-9.28t+16.43

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]

Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

Differentiate. Use the power rule:

P'(t)=6.10(2t)-9.28(1)

Simplify:

P'(t)=12.20t-9.28

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

P'(5)=12.20(5)-9.28

Multiply:

P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0
3 years ago
Sam makes about 79% of his free throws. he shoots 60 free throws. about how manywill he make?
nataly862011 [7]
Hey You!

60 * 79% = 47.4

You can solve it by:

(60 ÷ 100 × 79 = 47.4)

Sam will make 47.4 of his throws.
5 0
3 years ago
Read 2 more answers
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