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2 years ago

Solve n³ + 2n² - 15n = 0 by factoring. Show the factored form of the equation, and the resulting solutions.

Mathematics

2 answers:

Semenov [28]2 years ago

5 0

Answer: n = 0

n = 3

n = - 5

Step-by-step explanation:

The given cubic equation is expressed as

n³ + 2n² - 15n = 0

Since n is common to each term, we would factorize n out. It becomes

n(n² + 2n - 15) = 0

n = 0 or

n² + 2n - 15 = 0

To further factorize the quadratic equation, we would would find two numbers such that their sum or difference is 2n and their product is - 15n². The two numbers are 5n and - 3n. Therefore,

n² + 5n - 3n - 15 = 0

n(n + 5) - 3(n + 5) = 0

(n - 3)(n + 5) = 0

n = 3 or n = - 5

laila [671]2 years ago

4 0

Step-by-step explanation:

Take n common

n(n²+2n-15)=0

now factorise the quadratic one as n when goes to RHS it becomes zero

n²-3n+5n-15=0

n(n-3)+5(n-3)=0

n=3,-5

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2 years ago

Given: ABCD trapezoid<br> BC=1.2m, AD=1.8m<br> AB=1.5m, CD=1.2m<br> AB∩CD=K<br> Find: BK and CK

stepladder [879]

Answer:

The value of BK is 3m and the value of CK is 2.4m.

Step-by-step explanation:

Given information: ABCD trapezoid

, BC=1.2m, AD=1.8m

, AB=1.5m, CD=1.2m

, AB∩CD=K.

Using the given information draw a figure.

Two sides of a trapezoid are parallel.

Since AB∩CD=K, therefore AB and CD are not parallel, because parallel line never intersect.

$AD\parallelBC$

$\angle KBC=\angle KAD$ (Corresponding angles)

$\angle KCB=\angle KDA$ (Corresponding angles)

By AA rule of similarity

$\triangle KBC\sim \triangle KAD$

Corresponding sides of similar triangles are proportional.

$\frac{KB}{KA}=\frac{KC}{KD}=\frac{BC}{AD}$

$\frac{x}{x+1.5}=\frac{y}{y+1.2}=\frac{1.2}{1.8}$

$\frac{x}{x+1.5}=\frac{1.2}{1.8}$

$\frac{x}{x+1.5}=\frac{2}{3}$

$3x=2x+3$

$x=3$

The length of BK is 3 m.

$\frac{y}{y+1.2}=\frac{1.2}{1.8}$

$\frac{y}{y+1.2}=\frac{2}{3}$

$3y=2y+2.4$

$y=2.4$

The length of CK is 2.4 m.

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2 years ago

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Alex73 [517]

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3 years ago

Keri is simplifying 5·10^−3.

11111nata11111 [884]

Answer:

1. D

2. A

Step-by-step explanation:

Q1. Kerry is simplifying $5\cdot 10^{-3}$

By the definition of negative powers,

$a^{-n}=\dfrac{1}{a^n}$

Hence,

$10^{-3}=\dfrac{1}{10^3}$

So, the first step in simplifying the expression is

$5\cdot 10^{-3}=5\cdot \dfrac{1}{10^3}$

Q2. Given the expression

$\dfrac{8}{10^{-2}}$

First, use the definition of negative powers:

$10^{-2}=\dfrac{1}{10^2}$

Thus,

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2 years ago