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Inessa [10]
2 years ago
8

(12+34)×2.3= (talk to me please please please)​

Mathematics
2 answers:
Dimas [21]2 years ago
6 0

Answer:

105.8 is the answer

Step-by-step explanation:

105.8

serg [7]2 years ago
5 0

Answer:

90.2

Step-by-step explanation:

thx for the follow!!!

You might be interested in
The ________________ measures the spread of the middle 50% of the data set.
Scilla [17]

Answer:

C. interquartile range

Step-by-step explanation:

using this to show im right

"The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest."

Hope This Helped

6 0
2 years ago
Which equation is true?
enot [183]
Lets solve all of these:-

#1

√361 = 361 · 2
         
         ?
√361 = 361 · 2
√361 = 19
361 · 2 = 722

19 ≠ 722
So this equation is not true

#2:-

√361 = 19²

         ?
√361 = 19²
√361= 19
19² = 19 · 19 = 361

19 ≠ 361
So this equation is not true

√361 = 361 ÷ 2 

         ?
√361 = 361 ÷ 2 
√361 = 19
361 ÷ 2 = 180.5

√361 ≠ 361 ÷ 2 
So this equation is not true

√361 = √19²
√361 = 19
√19² = 19

19 = 19

SO the last one is right. Hope I helped ya!! xD
4 0
3 years ago
I need help on my warm up!! pls thx!
xxMikexx [17]

Step-by-step explanation:

\tt{30.16 = 17.56 + 5x}

Swap the sides of the equation :

⤑ \tt{17.56 + 5x = 30.16}

We want to remove the 17.56 first.

Since the original equation is 17.56 , we are going to use the opposite operation and subtract 17.56 from both sides :

⤑ \tt{5x + 17.56 - 17.56 = 30.16 - 17.56}

Simplify. 17.56 - 17.56 = 0 on the left. 30.16 - 17.36 = 12.6 on the right.

⤑ \tt{5x = 12.6}

Then, we need to think about how to remove the coefficient 5. Since the opposite of multiplication is division , I am going to divide both sides by 5.

⤑ \tt{ \frac{5x}{5}  =  \frac{12.6}{5}}

Simplify. 5/5 = 1 on the left and 12.6/5 = 2.52 on the right. So, Our answer is x = 2.52.

\pink{ \boxed{ \boxed { \tt{Our \: final \: answer :  \underline{ \underline{ \bold{ \tt{x = 2.52}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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7 0
3 years ago
5 Anita is using 36 cards to set up a card game. She wants to make
serious [3.7K]

Answer:

box is there so I'll put the money in the post

3 0
2 years ago
Inveres laplace transform (3s-14)/s^2-4s+8​
Olenka [21]

Complete the square in the denominator.

s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4

Rewrite the given transform as

\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}

Now take the inverse transform:

L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}

5 0
2 years ago
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