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bezimeni [28]
3 years ago
13

What is the solution to the equation 3(2x+5) = 3х+4x?

Mathematics
2 answers:
charle [14.2K]3 years ago
7 0

3(2x+5) = 3x+4x\\6x+15=7x\\x=15

elena-14-01-66 [18.8K]3 years ago
5 0

Answer:

x = 15

Step-by-step explanation:

Given

3(2x + 5) = 3x + 4x ← collect like terms

3(2x + 5) = 7x ← distribute parenthesis on left side by 3

6x + 15 = 7x ( subtract 6x from both sides )

15 = x ⇒ x = 15

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Solve 6 2/3 -1 1/2+4 1/6​
Tju [1.3M]

Answer:

9 1/3

Step-by-step explanation:

Make 2/3 , 1/2 , & 1/6 have the same denominator. 6 is the least common multiple for all 3 fractions.

2/3 gets multiplied by 2/2

1/2 gets multiplied by 3/3

1/6 stays the same

2/3 becomes 4/6

1/2 becomes 3/6

1/6 stays 1/6

Follow the order of operations from the original equation.

4/6 - 3/6 = 1/6 then 1/6 + 1/6 = 2/6

6 - 1 = 5 then 5 + 4 = 9

Simplify 2/6 to 1/3

Remember to add 1/3 back to 9 making it 9 1/3

8 0
3 years ago
-4(9 + 6) = plz help me
Arlecino [84]

Greetings, the answer is 11.

5 0
3 years ago
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The radius of a circle is 1 in. What is the circle's area? (Take a=3.14)
Kitty [74]

Answer:

3.14 inches

Step-by-step explanation:

area of circle = πr²

=> 3.14 x 1 x 1

=> 3.14 inches

8 0
2 years ago
Read 2 more answers
In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?
Mrac [35]

Answer:

Cosec <F = 73/55

Step-by-step explanation:

In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?

First you must know that;

Cosecant <F = 1/sin<F

Given

∠G=90°, GF = 48, EG = 55, and FE = 73.

ED ,= hyp = 73

EG = opp = 55*side facing <F

Using DOH CAH TOA

Sin theta = opp/hyp

Sin <F= 55/73

Reciprocate both sides

1/sinF = 73/55

Cosec <F = 73/55

3 0
3 years ago
This question is Twelfth grade math please help fast .<br><br> 2x - (2y + 5) = 8
DENIUS [597]

You cannot solve this. TO solve both variables you need to have two equations. Please insert that equation in and I will solve this problem. :)

8 0
2 years ago
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