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kenny6666 [7]
3 years ago
9

What is the sum of all positive integers n ≤ 20 that satisfy the condition that if n is odd, then n is a multiple of 5? I will g

ive brainliest for the correct answer AND explanation (It is not 20)
Mathematics
1 answer:
irinina [24]3 years ago
8 0

The sum of all positive integers that satisfy the condition as described is; 100

The number set of n is therefore;

n = {1, 2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}.

According to the question;

  • If n is odd, then n is a multiple of 5.

The data set therefore includes all odd numbers; This is so because the question says; if n is odd; then n is a multiple of 5.

The sum of all positive integers that satisfy the condition is therefore;

  • 1 + 3 +5 +7 + 9 +11 +13 +15 +17 +19 = <em>100.</em>

<em>Read </em><em>more:</em>

brainly.com/question/18837188

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The <u>congruency theorem</u> gives you an opportunity to prove that <u>two triangles</u> are <u>congruent</u>.

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