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harkovskaia [24]
4 years ago
15

I need help please Ok

Mathematics
1 answer:
sergeinik [125]4 years ago
5 0
What’s the question????
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P(x) = x^4+ax^3-x^2+bx-12 has factors of (x-2) and (x+1). Solve the equation P(x)=0​
Feliz [49]

Answer:

because P(x) has factors of (x-2) and (x+1) => x = 2 and x = -1 are the solutions of P(x)

so we have:

\left \{ {{2^{4}+2^{3}a-2^{2}+2b-12   =0} \atop {1-a-1-b-12=0}} \right.\\=>\left \{ {{8a+2b=0} \atop {a+b=-12}} \right.\\\left \{ {{4a+b=0} \atop {a+b=-12}} \right.\\\left \{ {{a=4} \atop {b=-16}} \right.

=> P(x)=x^{4} + 4x^{3}-x^{2} -16x-12

With P(x) = 0

=> x^{4}+4x^{3}-x^{2} -16x-12 = 0

=> ........

Step-by-step explanation:

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3 years ago
Coldwell elementary has a goal to collect 1,500 box tops in 6 months. the pta brought 458 box tops within two weeks. write and s
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