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djverab [1.8K]
3 years ago
11

Answer the following: GCF of 20 & 32 GCF of 45 & 75

Mathematics
2 answers:
earnstyle [38]3 years ago
5 0

Answer:

1. : 4

2. : 15

Step-by-step explanation:

Factors for 20: 1, 2, 4, 5, 10, 20

Factors for 32: 1, 2, 4, 8, 16, 32

Looking at the factors, we can see that the largest factor 20 and 32 have in common is 4. The answer isn't 1 or 2 because we are looking for the <u>greatest</u> common factor. This means we are looking for the largest of the factors which they both share.

Factors of 45: 1 , 3 , 5 , 9 , 15 , and 45.

Factors of 75: 1 , 3 , 5 , 15 , 25 and 75

Looking at these factors, we can see that 15 is the largest factor that 45 and 75 both share. The answer is not 1, 3, or 5 because we are again looking for the GREATEST common factor.

If my answers and explanations helped. Please say thanks! It means a lot to know my work is helping others achieve their academic goals. If you learned something from this, tell me! If you have any further questions, please comment and ask!

Jet001 [13]3 years ago
3 0

Answer:

GCF OF 20 AND 32: 4

Gcf of 45 and 75: 15

Step-by-step explanation:

GcF of 20 and 32

Factors of 20: 1, 2, 4, 5, 10, 20

Factors of 32: 1, 2, 4, 8, 16, 32

COMMON FACTORS: 1, 2, 4

GCF:4

Gcf of 45 and 75

Factors of 45: 15, 9, 5, 3, 1.

Factors of 75: 25, 15, 5, 3, 1.

CommoN factors: 1, 3, 5, 15

GCF:15

HOPE OT HELPED

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Step-by-step explanation:

Multiply the top by the top, and the bottom by the bottom:

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jeka94

Answer:

y = -0.85 + 0.09x; $49.82

Step-by-step explanation:

1. Calculate Σx, Σy, Σxy, and Σx²  

The calculation is tedious but not difficult.

\begin{array}{rrrr}\mathbf{x} & \mathbf{y}  & \mathbf{xy} & \mathbf{x^{2}}\\526 & 52.08 & 27394.08 & 276676\\625& 59.00 & 36875.00 &390625\\589 & 56.12 & 33054.68 & 346921\\409 & 25.72 & 10519.48 & 167281\\489 & 34.12& 16684.68 & 293121\\500 & 53.00 & 26500.00 &250000\\906 & 76.48 & 71102.88 & 820836\\251 &26.08 & 6546.08 & 63001\\595 & 50.60 & 30107.00 & 354025\\719 & 68.52 & 49265.88 & 516961\\\mathbf{5609} & \mathbf{503.72} &\mathbf{308049.76} & \mathbf{3425447}\\\end{array}

2. Calculate the coefficients in the regression equation

a = \dfrac{\sum y \sum x^{2} - \sum x \sum xy}{n\sum x^{2}- \left (\sum x\right )^{2}} =  \dfrac{503.7 \times 3425447 - 5609 \times 308049.76}{10 \times 3425447- 5609^{2}}\\\\= \dfrac{1725466163 - 1727851103.84}{34254470 - 31460881} = -\dfrac{2384941}{2793589}= \mathbf{-0.8537}

b = \dfrac{n\sumx y  - \sum x \sumxy}{n\sum x^{2}- \left (\sum x\right )^{2}} = \dfrac{3080498 - 2825365.48}{2793589} = \dfrac{255132}{2793589} = \mathbf{0.09133}

To two decimal places, the regression equation is

y = -0.85 + 0.09x

3. Prediction

If x = 563,

y = -0.85 + 0.09x = -0.85 + 0.09 × 563 = -0.85  + 50.67 = $49.82

(If we don't  round the regression equation to two decimal places, the predicted value is $50.56.)

 

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